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Oksi-84 [34.3K]
3 years ago
8

Science: Which statement is true about star A

Physics
1 answer:
Elza [17]3 years ago
6 0

Answer:

no clue

Explanation:

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1b) the atom could lose its valence electron

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Pigments that ABSORB all colors look _____.<br> Pigment that REFLECT all colors look _____.
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Lava is rock that has undergone a physical change and has liquefied. What is known about this change?
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Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
BabaBlast [244]

Answer:

<h2>E. 650N</h2>

Explanation:

step one:

given

length of stretcher= 2m

weight of stretcher=100N

Wayne weighs =800N

distance of Wayne weighs from chris's end= 75cm= 0.75m

The force that Chris is exerting to support the stretcher, with Wayne on it, can be computed by taking moments of the weight of the stretcher and Wayne weighs  about Chris's end, the end result is the reaction at Chris's end

Taking moment about Chris's end

The moment of Wayne weight 75cm from Chris+ Half the weight of stretcher 1m from Chris

0.75*800+50*1=0

600+50=0

650N

6 0
3 years ago
The lighting needs of a storage room are being met by six fluorescent light fixtures, each fixture containing four lamps rated a
Amanda [17]

Answer:

amount of energy  = 4730.4 kWh/yr

amount of money = 520.34 per year

payback period = 0.188 year

Explanation:

given data

light fixtures = 6

lamp = 4

power = 60 W

average use = 3 h a day

price of electricity = $0.11/kWh

to find out

the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66

solution

we find energy saving by difference in time the light were

ΔE = no of fixture × number of lamp × power of each lamp × Δt

ΔE is amount of energy save and Δt is time difference

so

ΔE = 6 × 4 × 365 ( 12 - 9 )

ΔE = 4730.4 kWh/yr

and

money saving find out by energy saving and unit cost that i s

ΔM = ΔE × Munit

ΔM = 4730.4 × 0.11

ΔM = 520.34 per year

and

payback period is calculate as

payback period = \frac{excess initial cost}{\Delta M}

payback period = \frac{32 + 66}{520.34}

payback period = 0.188 year

8 0
3 years ago
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