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Kay [80]
3 years ago
10

A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s

, what is the velocity of the sandbag?
Physics
1 answer:
marishachu [46]3 years ago
3 0

solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

d = 0*4.0 + 1/2*9.8*4.0^2

d = 78.4 m

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You need to consider the following:
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<span>
Formula:
 F = G * M1M2/r^2 
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 = 2.72x10^-5 
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Since,
1/2.72x10^-5 = 36800
The fraction ratio is  1/36800
</span>= <span>9.56x10^17 N</span>
3 0
3 years ago
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How do you work out Potential Difference??? <br> Please can you make it simple :) <br> Thanks.
patriot [66]

Answer:

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7 0
3 years ago
Read 2 more answers
What is the value for the kinetic energy for a n = 5 Bohr orbit electron in zeptoJoules?
Ne4ueva [31]

Answer:

The kinetic energy is 86.6 zepto joules.

Explanation:

Given that,

Number of orbit n =5

We know that,

Bohr's radius for hydrogen atom is

r = 0.53\times10^{-10}\times n^2\ m

Now, put the value of n in the formula of radius

r=0.53\times10^{-10}\times5^2

r =1.33\times10^{-9}\ m

We need to calculate the kinetic energy

Using formula of kinetic energy

E_{k}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{e^2}{2\times r_{s}}

Put the value into the formula

E_{k}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times1.33\times10^{-9}}

E_{k}=8.66\times10^{-20}\ J

We know that,

1\ zepto\ joule=1\times10^{-21}\ J

The kinetic energy is

E_{k}=\dfrac{8.66\times10^{-20}}{1\times10^{-21}}

E_{k}=86.6\ zepto\ Joules

Hence, The kinetic energy is 86.6 zepto joules.

8 0
3 years ago
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