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natita [175]
2 years ago
5

According to the Second Law of Thermodynamics, a. any process during which the entropy of the universe increases will be product

-favored. b. heat will always be transferred from a cooler object to a warmer object. c. any process during which the entropy of the system increases will be product-favored. d. any process which is endothermic will be product-favored. e. the total amount of matter in the universe remains constant.
Physics
1 answer:
Iteru [2.4K]2 years ago
4 0

Answer:

The correct option is;

a. Any process in which the entropy of the universe increases will be product-favored

Explanation:

According to the second law of thermodynamics, the change in entropy of a closed system with time is always positive. That is the entropy of the entire universe, considered as an isolated system, always increases with time, hence the entropy change in the universe will always be positive.

\Delta S_{universe} = \Delta S_{system}  + \Delta S_{surroundings} >0

Therefore, any process in which the entropy of the universe increases will be product favored.

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A thin taut string is fixed at both ends and stretched along the horizontal x-axis with its left end at x = 0. It is vibrating i
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Answer:

(a) Wavelength is 0.436 m

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Solution:

As per the question:

The eqn of the displacement is given by:

y(x, t) = (1.22 cm)sin[14.4 m^{- 1}x]cos[(166\ rad/s)t]          (1)

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Now, on comparing eqn (1) and (2):

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Now, to calculate the string's wavelength,

(a) K = \frac{2\pi}{\lambda}

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K = propagation vector

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\lambda = \frac{2\pi}{14.4} = 0.436\ m

(b) The length of the string is given by:

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f = \frac{2\pi}{166} = 26.42\ Hz

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Speed of the wave is given by:

v = f\lambda

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