Question

Find the value of given expressionrmula1" title=" \sqrt{4} \times (2)" alt=" \sqrt{4} \times (2)" align="absmiddle" class="latex-formula">
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Answer 1

Step-by-step explanation:

Given

[tex] \sqrt{4} \times (2) \\ \sqrt{ {2}^{2} } \times 2 \\ = 2 \times 2 \\ = 4

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Answer 2

Look at the explanation to understand.

Step-by-step explanation:

Step 1.

Apply the rule. (a) = a

For this expression, (2) = 2

$\sqrt{4}\times2$

Step 2.

Multiply 4 by 2.

4 × 2 = 8

Step 3.

Prime factorization of 8: 2³

$\sqrt{2^3}$

Step 4.

Apply the exponent rule. $(a^b^+^c=a^b\times a^c)$

2³ = 2² × 2

$\sqrt{2^2\times2}$

Step 5.

Apply the radical rule. $\sqrt{ab}=\sqrt{a}\sqrt{b}, a\geq 0, b\geq 0$

$\sqrt{2^2}\sqrt{2}$

Step 6.

Apply the radical rule again. $\sqrt{a^2}=a, a\geq 0$

$2\sqrt{2}=4$

Hence, 4 is the answer.