A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.19. They have also deter
2 answers:
Answer:
0.03
Step-by-step explanation:
The given question uses the concept of Conditional Probability. The general formula of conditional probability in terms of two events A and B is:
In the given case, the two events are:
LC = Event that someone has lung cancer
S = Event that someone is smoker
The formula in terms of these events will be:
Using the given values, we can find the probability that a random person is a smoker and has lung cancer P(S∩LC).
Therefore, the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC) is 0.03
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Answer:
(a) -2.8
b) (1) Reject H0: p = 0.50 in favor of HA: p < 0.50; there is sufficient evidence to conclude that less than half of all UGA female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.
Step-by-step explanation:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
H0: p = 0.50
This means that:
In a random sample of 305 UGA female students, 128 responded that, if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.
This means that
a) Value of the test statistic:
Pvalue:
We are testing the hypothesis that the proportion is less than 0.5, which means that the pvalue of the test is the pvalue of z = -2.81.
Looking at the z-table, z = -2.8 has a pvalue of 0.0026
(b) What is the correct conclusion for this hypothesis test at the 0.05 level of significance?
0.0026 < 0.05, which means that we reject the null hypothesis, that the proportion is 0.5, and accept the alternate hypothesis, that the proportion is less than 0.5, option (1).