Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
1. The range is the possible values for the y-coordinate in a relation or a set of data pairs.
The range is {nine, ten, eight, five, four, two}
2. If you plot the given points, then you'd see that that point
(three, nine) is far from the rest of the other points which makes it an outlier. Other methods can be used to determine whether or not the point is really and outlier. For now, a visual inspection is enough.
Answer:
6
Step-by-step explanation:
Since the x coordinate is the same, we only have to look at the y coordinate
3 - -3 = 3 +3 = 6
The distance is 6
Answer:
y = 5x/2 + 2
Step-by-step explanation:
We know the equation for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since we have the coordinates of one point on this line and the slope, we can substitute that in and find b first:
y = mx + b
-8 = 5/2(-4) + b
-8 = -10 + b
b = 2
So we can use the slope and this y intercept we found to plug back into the equation:
y = mx + b
y = 5x/2 + 2
Answer:
The area of the figure is 28 units².
Step-by-step explanation:
Find the area of the full rectangle, ignoring the triangle.
Then, find the area of the triangle:
Finally, subtract:
