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Mkey [24]
3 years ago
15

Juan is working two summer jobs, making $12 per hour babysitting and making $16 per hour lifeguarding. In a given week, he can w

ork at most 17 total hours and must earn at least $240. If Juan worked 3 hours babysitting, determine all possible values for the number of whole hours lifeguarding that he must work to meet his requirements. Your answer should be a comma separated list of values. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
Semenov [28]3 years ago
6 0

\text{Let }b=

Let b=

\,\,\text{the number of hours babysitting}

the number of hours babysitting

\text{Let }l=

Let l=

\,\,\text{the number of hours lifeguarding}

the number of hours lifeguarding

\text{\textquotedblleft at most 17 hours"}\rightarrow \text{17 or fewer hours}

“at most 17 hours"→17 or fewer hours

Use a \le≤ symbol

Therefore the total number of hours worked in both jobs, b+lb+l, must be less than or equal to 17:17:

b+l\le 17

b+l≤17

\text{\textquotedblleft at least \$240"}\rightarrow \text{\$240 or more}

“at least $240"→$240 or more

Use a \ge≥ symbol

Juan makes $12 per hour babysitting, so in bb hours he will make 12b12b dollars. Juan makes $16 per hour lifeguarding, so in ll hours he will make 16l16l dollars. The total amount earned 12b+16l12b+16l must be greater than or equal to \$240:$240:

12b+16l\ge 240

12b+16l≥240

\text{Plug in }\color{green}{3}\text{ for }b\text{ and solve each inequality:}

Plug in 3 for b and solve each inequality:

Juan worked 3 hours babysitting

\begin{aligned}b+l\le 17\hspace{10px}\text{and}\hspace{10px}&12b+16l\ge 240 \\ \color{green}{3}+l\le 17\hspace{10px}\text{and}\hspace{10px}&12\left(\color{green}{3}\right)+16l\ge 240 \\ l\le 14\hspace{10px}\text{and}\hspace{10px}&36+16l\ge 240 \\ \hspace{10px}&16l\ge 204 \\ \hspace{10px}&l\ge 12.75 \\ \end{aligned}

b+l≤17and

3+l≤17and

l≤14and

​  

 

12b+16l≥240

12(3)+16l≥240

36+16l≥240

16l≥204

l≥12.75

​  

 

\text{The values of }l\text{ that make BOTH inequalities true are:}

The values of l that make BOTH inequalities true are:

\{13,\ 14\}

{13, 14}

\text{(the final answer is this entire list)}

(the final answer is this entire list)

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Answer:

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Step-by-step explanation:

Firstly, we need to calculate the total score of the junior students and the total score of the senior students.

The total score of the junior students is 35 * 80 = 2,800

The total score of the senior students is 15 * 70 = 1050

The total score is thus 2,800 + 1,050 = 3,850

The average score of the 50 students is thus 3,850/50 which equals 77

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Step-by-step explanation:

add his cash,car that's paid off,and his savings.

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3 years ago
9/17 15/34 6/17 9/34 geometric sequence?
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In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

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6 0
3 years ago
At the soup to nuts cafeteria, larry orders two pieces of toast and a bagel, which comes out to $\$1.30$. Curly orders a bagel a
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Let us take costs of a piece of toast = $t, , one bagel cost=$b and a muffin cost=$m.

Larry

Two pieces of toast and a bagel cost  = $1.30

2t+b=1.30   -------------equation(1)

Let us solve the equation(1) for t in terms of b, because we need to find one bagel cost.

Subtracting b from both sides we get

2t+b-b=1.30-b

2t= 1.30-b

Dividing by 2 on both sides.

2t/2= (1.30-b)/2

t= (1.30-b)/2

Curly

A bagel and a muffin cost = $2.50.

b + m = 2.50 -------------equation(2)

Solving equation for m in terms of b, we get

m= 2.50-b.

Moe

A piece of toast, two bagels, and three muffins cost = $6.95

t + 2b + 3m = 6.95    ......................equation(3).

Substituting t= (1.30-b)/2 and m= 2.50-b in equation (3)

(1.30-b)/2 + 2b + 3(2.50-b) = 6.95 .

Multiplying each term by 2 to get rid 2 from denominator of (1.30-b).

2*(1.30-b)/2 + 2*2b + 2*3(2.50-b) = 2*6.95

1.30-b + 4b + 6(2.50-b) = 13.90.

1.30 - b + 4b  +15 - 6b = 13.90

Combining like terms

-3b +16.30 = 13.90

Subtracting 16.30 from both sides.

-3b +16.30-16.30 = 13.90-16.30.

-3b= -2.4

Dividing both sides by -3.

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7 0
3 years ago
The table shows the number of cell phone towers a
Olin [163]

Answer:

The correct option is;

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Step-by-step explanation:

The given data can be presented as follows;

Cell Phone Towers

Customer (thousands)    {}   Towers

1) 5.25            {}                          273

2) 6.25            {}                         325

3) 7.25            {}                         377

4) 9.25            {}                         481

From the given data, we have the ratio Towers/Customer (thousands) given as follows;

For 1), we have;

273 Towers/(5.25 thousands customers) = 52 Towers/(Thousand customer)

For 2), we have;

325 Towers/(6.25 thousands customers) = 52 Towers/(Thousand customer)

For 3), we have;

377 Towers/(7.25 thousands customers) = 52 Towers/(Thousand customer)

For 4), we have;

481 Towers/(9.25 thousands customers) = 52 Towers/(Thousand customer)

Therefore, the ratios of towers to customers (thousands) all have the same equivalent unit rate of 52 Towers/(thousand customers).

6 0
3 years ago
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