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svet-max [94.6K]
3 years ago
9

True or false in Florida, the number of alcohols related traffic deaths increased in 2009 compared to 2008

Mathematics
1 answer:
NeX [460]3 years ago
3 0
False, they actually decreased some.
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What is x if a line passes though (2,5) ( x,3)
antoniya [11.8K]

Answer:

x = - 2

Step-by-step explanation:

Givens

(2,5)

(x,3)

m = 1/2

Formula

m = (y2 - y1)/(x2 - x1)

Solution

y2 = 3

y1 = 5

x2 = x

x1 = 2

1/2 = (3 - 5)/(x - 2)                 Cross multiply

1*(x - 2) = 2 (-2)                      Combine and remove the brackets.

x - 2 = - 4                               Add 2 to both sides

x = - 4 + 2

x = - 2

4 0
2 years ago
Please help me !! Simplify 5 - (-1)
sergiy2304 [10]

Answer:

6

Step-by-step explanation:

5+1

a negative and a negative make a positive.

=6

6 0
3 years ago
Read 2 more answers
Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
3 years ago
Good at graphing coordinates? I need some help on that please!
ohaa [14]
Here are the coordinates :)

4 0
3 years ago
which equation represents this sentence? five more than three times the number is one-third more than the sum of the number and
lidiya [134]
3n + 5 = (n + n) + 1/3
4 0
3 years ago
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