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<u>Answer:</u> The mass of iron (III) chloride produced is 14.81 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For iron(III) oxide:</u>
Given mass of iron(III) oxide = 10.0 g
Molar mass of iron(III) oxide = 159.7 g/mol
Putting values in equation 1, we get:
- <u>For hydrochloric acid:</u>
Given mass of hydrochloric acid = 10.0 g
Molar mass of hydrochloric acid = 36.5 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of iron (III) oxide and hydrochloric acid follows:
By Stoichiometry of the reaction:
6 moles of hydrochloric acid reacts with 1 mole of iron (III) oxide
So, 0.274 moles of hydrochloric acid will react with = of iron (III) oxide
As, given amount of iron (III) oxide is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
6 moles of hydrochloric acid produces 2 moles of iron (III) chloride
So, 0.274 moles of hydrochloric acid will produce = of iron (III) chloride
Now, calculating the mass of iron (III) chloride from equation 1, we get:
Molar mass of iron (III) chloride = 162.2 g/mol
Moles of iron (III) chloride = 0.0913 moles
Putting values in equation 1, we get:
Hence, the mass of iron (III) chloride produced is 14.81 grams