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jasenka [17]
3 years ago
11

A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co

ntainer at a temperature of 30oC. Ciron=0.444Jg∘C Cwater=4.184Jg∘C rhowater=1gmL 10. What is the final temperature of the water?
Chemistry
1 answer:
galben [10]3 years ago
4 0

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

-Q_1=Q_2

Mass of iron = m_1=20 g

Specific heat capacity of iron = c_1=0.444 J/g^oC

Initial temperature of the iron = T_1=120^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= m_2=300 mL\times 1 g/mL = 300 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=30^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

we get, T =  30.63°C

30.63 °C will be the final temperature of the water.

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Silver can be electroplated at the cathode of an electrolysis cell by the half-reaction. Ag+(aq)+e−→Ag(s) Part A Silver can be e
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Explanation: According to Faraday Law of Electrolysis, the mass of substance deposited at the electrode (cathode or anode) is directly proportional to quantity of electricity passed through the electrolyte

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