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3 years ago

Plzz help.me with both questions

Physics

1 answer:

Hatshy [7]3 years ago

5 0

Explanation:

Primary cell

1. They are non-rechargeable.

2. The energy density of primary cells is more.

3. The internal resistance of primary cells is more.

4. Example : Zinc-Carbon cell.

Secondary cells

1. They are rechargeable cells.

2. The energy density of secondary cells is less.

3. The internal resistance of secondary cells is less.

4. Example : Car batteries

Current :

The flow of electric charge per unit time is called electric current. It can be given by the formula as follows :

$I=\dfrac{q}{t}$

The SI unit of electric current is Ampere.

1 Ampere is defined as the current that flows with the electric charge of one Coulomb per second (C/s).

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Which of the following depicts xylem?

BlackZzzverrR [31]

C is the right image for that biological process.

8 0

3 years ago

The current in an electric hair dryer is 10

Vikki [24]

First let's convert the time in seconds:
$\Delta t= 5 min= 5 min \cdot (60 s/min)= 300 s$

The current is defined as the quantity of charge flowing through a certain section of a circuit per unit of time:
$I= \frac{Q}{\Delta t}$
Using I=10 A, and $\Delta t=300 s$ , we can find the amount of charge flown through the hair dryer in this time:
$Q=I \Delta t=(10 A)(300 s)=3000 C$

The charge of a single electron is $q=1.6 \cdot 10^{-19} C$ , so the number of electrons flown through the hair dryer is the total charge divided by the charge of a single electron:
$N= \frac{Q}{q}= \frac{3000 C}{1.6 \cdot 10^{-19} C} =1.88 \cdot 10^{22}$

8 0

4 years ago

Which of the following can be computed?

Musya8 [376]

Answer: only the third option. [Vector A] dot [vector B + vector C]

The dot between the vectors mean that the operation to perform is the "scalar product", alson known as "dot product".

This operation is only defined between two vectors, not one scalar and one vector.

When you perform, in the first option, the dot product of any ot the first and the second vectors you get a scalar, then you cannot make the dot product of this result with the third vector.

For the second option, when you perform the dot product of vectar B with vector C you get a scalar, then you cannot make the dot product ot this result with the vector A.

The third option indicates that you sum the vectors B and C, whose result is a vector and later you make the dot product of this resulting vector with the vector A. Operation valid.

The fourth option indicates the dot product of a scalar with the vector A, which we already explained that is not defined.

5 0

3 years ago

Use the following d/t graph to determine the velocity of the object

marin [14]

Answer:

1/3 m/s

Explanation:

Because the graph goes from 3 to 8 on the Y axis we know that each line is 0.5 and on the X axis each line is 1, Then, the slope , or velocity, is 1/3

see? This graph is kinda set up to throw you.

Is there a 1/3 option for this ??

5 0

2 years ago

Explain two scenarios where a large truck can have the same momentum as a small car.

KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

$p=mv\cdots(i)$

Let $M_L$ and $M_S$ be the masses of the large truck and the car respectively, and $V_L$ and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck $= M_LV_L$

and the momentum of the small car $= M_SV_S$ .

If the large truck has the same momentum as a small car, then the condition is

$M_LV_L=M_SV_S\cdots(ii)$

The equation (ii) can be rearranged as

$\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}$

So, the first scenario:

$\frac {M_L}{M_S}=\frac {V_S}{V_L}$

$\Rhghtarrow M_L:M_S=V_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

$\frac{M_L}{V_S}=\frac{M_S}{V_L}$

$\Rhghtarrow M_L:V_S= M_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0

3 years ago

Plzz help.me with both questions​

Plzz help.me with both questions