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1 year ago

What's the toughest animal in the world

Physics

2 answers:

eduard1 year ago

6 0

Explanation:

it can be giraffe.

if this helps you then please make me brainlist please

romanna [79]1 year ago

5 0

Answer:

In explanation

Explanation:

Toughest animal existing now would be like a bear more specifically a grizzly bear. I say this because when your near this animals and your messing with it or it's cubs your more than likely dead you climb up a tree,did you forget they can climb to,when running a grizzly bear can get up to a max speed of 35 MPH, Now the grizzly bear isn't the most aggressive but is still one of the rulers of bears along with it's relative the polar bear,but when you are talking about pain they can't take pain shoot them it takes more than 1 show better have a machine gun or be able to run fast a knife isn't going to do a lot in less you get it in it's eye. Now for a grizzly bear you can play dead and he will fall for it or she but all you need to know is don't mess with it.

Another one of the toughest animal is a komodo dragon.

When were talking about a komodo dragon there like a human they way up to 170 LBS to 200 LBS they have a length of 8 foot and a half. Now komodo dragons are very friendly and can be a family pet but if that thing bites you,you will be dead within hours in less treated amindentally. The komodo dragon can kill water buffalos, and the komodo dragon has no predators. The komodo dragon is the biggest lizard in the world and is poisonous so that is a reason to not get around with, one time a komodo dragon killed an eight year old boy so not really friendly.

is there anymore things you want my opinion on on actually the real deal.

would you like to know most aggressive,

most dangerous,

most poisonous,

The most feared

the most loving

The biggest animal in the world

The most friendly or other just let me know:)

Hope it helps have a great afternoon:)

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Two spectators at a soccer game see, and a moment later hear, the ball being kicked on the playing field. The time delay for the

WINSTONCH [101]

Answer:

a)188.65m

b)154.35m

c)243.7m

Explanation:

Given data:

$t_A=0.55s$

$t_B=0.45s$

(a) The distance from the kicker to each of the 2 spectators is given by:

$d_A=v \times t_A$

where,

v= speed of sound

$t_A$ =time taken for the sound waves to reach the ears

$d_A=343\times 0.55=188.65$ m

(b) $d_B=v \times t_B$

where,

v= speed of sound

$t_B$ =time taken for the sound waves to reach the ears

$d_B=343\times 0.45=154.35m$

(c)As the angle b/w slight lines from the two spectators to the player is right angle,

hypotenuse=the distance b/w 2 spectators

and, the slight lines are the other 2 lines

$D^2=d_A^2+d_B^2\\D=\sqrt{188.65^2+154.35^2} \\D= 243.7m$

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2 years ago

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3 years ago

What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.5 km/h and the μs

Yakvenalex [24]

Answer:

Radius=15.773 m

Explanation:

Given data

v=29.5 km/h=8.2 m/s

μs=0.435

To find

Radius R

Solution

The acceleration is a centripetal acceleration which is experienced by the bicycle given by

$a=v^{2}/R$

This acceleration is only due to static force which given as

$f=ma\\f=m(v^{2}/R )$

The maximum value of the static force is given as

$Fs_{max}=u_{s}F_{N}$

where

FN is normal force equal to mass*gravity

Therefore when the car is on the verge of sliding

$f=fs_{max}\\ m(v^{2}/R )=u_{s}mg$

Therefore the minimum radius should be found by the bicycle move without sliding

$v^{2}/R=u_{s}g\\ R=v^{2}/u_{s}g\\R=(8.2)^{2}/(0.435*9.8)\\R=15.773m$

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3 years ago

| A T-ball with a mass of 0.6 kg travels in the

r-ruslan [8.4K]

Answer:

$|I|=6\ Kg.m/s$

$F=120\ N$

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

$p_o=m.v_o$

When a force is applied, the speed changes to $v_1$ and the new momentum is

$p_1=m.v_1$

The change of momentum is

$\Delta p=p_1-p_0=m(v_1-v_o)$

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

$I=F.t=\Delta p$