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zlopas [31]
3 years ago
7

What is the momentum of an object that is moving in a straight line at a speed of 10 m/s and has a mass of 10 kilograms?

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0
The momentum of an object is given by the product between its mass and its velocity:
p=mv
where m is the mass and v the velocity.

For the object in our problem, m=10 kg and v=10 m/s, therefore its momentum is
p=mv=(10 kg)(10 m/s)=100 kg m/s
So, the correct answer is B).
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Sholpan [36]

Answer:

2. By vibrations in wires or strings.

8 0
4 years ago
Difference between interpolation and extrapolation.
AlladinOne [14]

Answer:

Interpolation gives more accurate data or points compared to extrapolation.

Interpolation can be a little easier than extrapolation.

Interpolation does not require one to extend the already existing data points, where extrapolation requires elaboration of the pattern, curve, or line.

Extrapolation:

This is a statistical method used to predict unknown values for points outside the range of the recorded data. It is used to extend a known sequence of values beyond the sampled area

Extrapolation: with Extrapolation, we can be less confident with the unknown values derived using this method. The method includes values from outside the sampled area, which makes the predictions diverge away from the true values. In curve fitting, this method is not preferred.

Extrapolation:

the ability to retrieve negative answers is one characteristic that makes it unique for interpolation. This statistical method allows one to extend the values in the range either forward or backward. This technique of extending values is responsible for attaining the negative values.

Explanation:

8 0
3 years ago
A hydrogen fuel cell supplies power for a small motor. the fuel cell delivers a current of 0.5 a and a voltage of 0.43 v. what i
gogolik [260]
We want to know what is the power supplied by the power cell if the current I=0.5 A and the voltage V=0.43 V. The equation for power P is P= I*V, so:

P=I*V=0.5*0.43=0.215 W

So the correct answer is that the power cell is supplying the motor with P=0.215 W of power. 
8 0
3 years ago
A solid cylindrical bar conducts heat at a rate of 25 W from a hot to a cold reservoir under steady state conditions. If both th
expeople1 [14]

Answer:

Using the new cylinder the heat rate between the reservoirs would be 50 W

Explanation:

  1. Conduction could be described by the Law of Fourierin the form: Q=kA\frac{T_1-T_2}{L} where Q is the rate of heat transferred  by conduction, k is the thermal conductivity of the material, T_1 and T_2 are the temperatures of each heat deposit, A is the cross area to the flow of heat, and {L} is the distance that the flow of heat has to go.
  2. For the original cylinder the Fourier's law would be: kA_1\frac{T_1-T_2}{L_1}=25W, and if A_1=\frac{\pi D_{1}^{2}}{4}, then the expression would be:k\frac{\pi D_1^{2}}{4} \frac{T_1-T_2}{L_1}=25W where D_1 is the diameter of the original cylinder, and {L_1} is the length of the original cylinder.
  3. For the new cylinder, in the same fashion that for the first, Fourier's Law would be: Q_2=k\frac{\pi D_2^2}{4}\frac{T_1-T_2}{L_2},where Q_2 is the heat rate in the second case, D_2 and {L_2 are the new diameter and length.
  4. But, D_2=2D_1 and L_2=2L_1, substituting in the expression for Q_2: Q_2=k\frac{\pi (2D_1)^2}{4}\frac{T_1-T_2}{2L_1}.
  5. Rearranging: Q_2=\frac{2^2}{2}(k\frac{\pi D_1^2}{4}\frac{T_1-T_2}{L_1}).
  6. In the last declaration of  Q_2, it could be noted that the expressión inside the parenthesis is actually  Q_1, then:  Q_2=\frac{2^2}{2}(25W)=50W.
  7. <u>It should be noted, that the temperatures in the hot and cold reservoirs never change.</u>
7 0
4 years ago
Changing the velocity of a moving object will have little effect on its kinetic energy.
Alinara [238K]

Answer:Faulse

Explanation:

5 0
4 years ago
Read 2 more answers
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