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2 years ago

What is the momentum of an object that is moving in a straight line at a speed of 10 m/s and has a mass of 10 kilograms?

1 answer:

8 0

The momentum of an object is given by the product between its mass and its velocity:
$p=mv$
where m is the mass and v the velocity.

For the object in our problem, m=10 kg and v=10 m/s, therefore its momentum is
$p=mv=(10 kg)(10 m/s)=100 kg m/s$
So, the correct answer is B).

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A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w

ExtremeBDS [4]

Intensity of electromagnetic wave is given as

$I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]$

given that

$I = 0.0275 W/m^2$

$0.0275 = \frac{B_{rms}^2}{\mu_0} \times c$

here we know that

$\mu_0 = 4\pi \times 10^{-7}$

$c = 3 \times 10^8 m/s$

now we have

$0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)$

$B_{rms} = 1.07 \times 10^{-8} T$

now we will have

$B_0 = \sqrt2 B_{rms}$

$B_0 = 1.52 \times 10^{-8} T$

frequency of wave is given as

$f = \frac{c}{\lambda}$

$f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz$

now the induced EMF is given as

$EMF = B_0A2\pi f$

$EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)$

$EMF = 0.0733 Volts$

7 0

3 years ago

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1. As a person stands on earth they put a force on the ground and the ground puts a force on them.

Scorpion4ik [409]

Answer:

Explanation:

m b

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2 years ago

What is the nucleus of the atom

luda_lava [24]

Answer:

An atomic Nucleus

Explanation:

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3 years ago

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Why do astronomers use spectroscopes to analyze light from distant objects?

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7 0

3 years ago

An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration

lana [24]

Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward = g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward = g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁ = 9.8 - 3 = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

⇒ Vf² = 53. 125

⇒ Vf= 7.29 m/s

8 0

3 years ago