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Evgen [1.6K]
3 years ago
15

What is the single matrix that would transform a pre-image according to the following (in order):

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

Step-by-step explanation:

That's all I know sorry

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Solve the differential equation: dy/dx = 4y2x1/3
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The first thing you should do is use the method of variable separation. Then, integrate both sides to find the solution.
 In this case the answer is
  <span>D. - 1/y = 3x4/3 + C</span> 
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Prove that Sin2(90-theta)(1+cot2(90-theta))=1
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Step-by-step explanation:

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8 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
A solid oblique pyramid has a square base with edges measuring x cm. The height of the pyramid is (x + 2) cm. Which expression r
zavuch27 [327]

we know that

the volume of a solid oblique pyramid is equal to

V=\frac{1}{3}*B*h

where

B is the area of the base

h is the height of the pyramid

in this problem we have that

B is a square

B=b^{2}

where

<u>b=x\ cm</u>

so

B=x^{2}\ cm^{2}

h=(x+2)\ cm

substitute in the formula of volume

V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

therefore

<u>the answer is</u>

V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

4 0
3 years ago
Read 2 more answers
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