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2 years ago

Based on histogram above what is the average number of hours worked by 20 salesperson in company G

Mathematics

1 answer:

kiruha [24]2 years ago

3 0

Answer:

$Average = 38$

Step-by-step explanation:

Given

The attached histogram

Required

The average work hours by 20 salespeople

First, we get the total hours worked as follows:

$Hours = 3 * 30 + 5 * 34 + 9 * 40 + 2 * 45 + 1 * 50$

$Hours = 760$

Divide by number of salespeople

$Average = Hours/n$

$Average = 760/20$

$Average = 38$

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Considere as seguintes afirmações: I. O inverso de 0,2 é 5. II. O triplo de \frac{2}{5} é \frac{6}{15}. III. A metade de 0,5 é \

Alex777 [14]

Answer:

I e III

Step-by-step explanation:

Recebemos declarações na questão acima para considerar.

Declaração I. O inverso de 0,2 é 5.

Matematicamente, isso é escrito como:

1 / 0,2

0,2 = 2/10

Portanto: 1 ÷ 2/10 = 1 × 10/2

= 5

Afirmação 1 é verdadeira

Declaração II.

O triplo de 2/5 é 6/15.

Triplo de 2/5 = 2/5 + 2/5 + 2/5

= 2 + 2 + 2/5

= 6/5

= 1 1/5

Declaração II é falsa

III. A metade de 0,5 é 1/5

1/2 de 0,5

= 1/2 × 0,5 = 0,25

Convertendo em fração

= 0,25 = 25/100

= 1/4

Declaração III está correta

Portanto, as afirmações verdadeiras são I e III

8 0

2 years ago

What is the square root of 21

Andru [333]

Answer:

4.58

Step-by-step explanation:

21 is not a perfect square, but lies between the perfect squares 16 and 25. Thus, √21 lies between √16 and √25, that is, between 4 and 5. Since 21 is closer to 25 than to 16, √21 is closer to 5 than to 4. A rough estimate of √21 would be 4.7.

√21 done on a calculator comes out to 4.58.

4 0

2 years ago

Your typical markup for merchandise is 40%. your cost on an item is $8.00. calculate the selling price.

adoni [48]

The selling price would be $11.20.

40% = 40/100 = 0.4

The mark up is 40% of the cost; this means 40% of 8:

40% of 8 = 0.4(8) = 3.20
8 + 3.20 = 11.20

6 0

3 years ago

27.) Find the sum of the length of line segments EF and CD

Lelechka [254]

Answer:

5√10

Step-by-step explanation:

The distance between two points A( $x_1,y_1$ ) and B( $x_2,y_2$ ) on the coordinate plane is given by:

$|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }$

From the image attached the coordinates of the points are E(-1, -1), F(8, -4), C(-7, -4) and D(-1, 2).

Hence the lengths of the line segment EF and CD are:

$|EF|=\sqrt{(8-(-1))^2+(-4-(-1))^2} =\sqrt{90}=3\sqrt{10} \\\\CD=\sqrt{(-1-(-7))^2+(-2-(-4))^2}=\sqrt{40} =2\sqrt{10} \\\\Therefore:\\\\|EF|+|CD|=3\sqrt{10} +2\sqrt{10} =5\sqrt{10}$

6 0

2 years ago

I need these from least to greatest A.11^4/11^11 B.1/11^-4 C.(11^-3)^-3 D.11^5•11^2

Sliva [168]

Answer:

$\frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} } < {11}^{5} . {11}^{2} < ( {11}^{ - 3} )^{ - 3}$

Step-by-step explanation:

$A) \frac{ {11}^{4} }{ {11}^{11} } = {11}^{4 - 11} = {11}^{ - 7} \\ \\ B)\frac{1}{ {11}^{ - 4} } = {11}^{4} \\ \\C) ( {11}^{ - 3} )^{ - 3} = {11}^{ - 3( - 3)} = {11}^{9} \\ \\ D){11}^{5} . {11}^{2} = {11}^{5 + 2} = {11}^{7} \\ \\ \because \: {11}^{ - 7} < {11}^{4} < {11}^{7} < {11}^{9} \\ \\ \therefore \: \frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} } < {11}^{5} . {11}^{2} < ( {11}^{ - 3} )^{ - 3}$

6 0

2 years ago

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