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3 years ago

If (x+1) is a factor of x^3+2x^2-x-2, find the remaining factors.

Mathematics

2 answers:

Alexxandr [17]3 years ago

8 0

Using synthetic division to divide x³ + 2x² - x - 2. Since (x + 1) is the factor, we can divide by -1. See the attached file for the synthetic division. After that, we are left with x² + x - 2. This can easily be factored into (x + 2)(x - 1). The remaining factors are (x + 2) and (x - 1).

mihalych1998 [28]3 years ago

8 0

Answer:

The other factors are (x-1) and (x+2).

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Use the numbers to complete the ordered pairs that represent the endpoints of line segment YZ

lukranit [14]

Answer:

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Step-by-step explanation:

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2 years ago

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Katyanochek1 [597]

Answer:

b/a
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Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

What is the slant height of a square pyramid that has a surface area of 319 square feet and a side length of 11 feet?

Dafna1 [17]

Step-by-step explanation:

Surface area of a square pyramid is the area of the square base plus the area of the four triangles made from the base and the slant height.

SA = s² + 4(sh/2)

which reduces to:

SA = s² + 2sh

You are told that s = 11 and SA = 319. You can now solve for h:

319 = 11² + 2(11)h

319 = 121 + 22h

198 = 22h

h = 9 ft (answer C)

I hope it's helpful!!

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3 years ago

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a polygon has an area of 225 square meters. A similar polygon is created with an area that is triple the first. By what factor i

GuDViN [60]

The area of the original polygon is:
A = 225 m ^ 2
The similar polygon area is:
A '= (k ^ 2) * (A)
Substituting values:
3 * 225 = (k ^ 2) * (225)
Clearing k we have:
k ^ 2 = 3
k = (3) ^ (1/3)
Answer:
The length of each side increased by:
k = (3) ^ (1/3)

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3 years ago

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belka [17]

the most groups she can have is 10

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3 years ago

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