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Alisiya [41]
3 years ago
7

11/12 - (-10) - 5/6 as a single rational number

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

121/12

Step-by-step explanation:

1. 11/12 - (-10) = 11/12+10 = 131/12

2. 131/12-5/6 = 131/12 - 10/12 = 121/12

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The data show prices of light bulbs at a home improvement store, rounded to the nearest dollar. Find the interquartile range (IQ
Yuliya22 [10]

Answer:

The interquartile range (IQR) of the data set is  <u>8</u>.

Step-by-step explanation:

Given:

The data show prices of light bulbs at a home improvement store, rounded to the nearest dollar.

5, 2, 8, 10, 2, 20, 6, 15, 29, 6, 2, 2, 5, 1, 3.

Now, to find the interquartile range (IQR) of the data set.

So, we arrange first in orders:

1,2,2,2,2,3,5,5,6,6,8,10,15,20,29.

Now, to get the median:

1,2,2,2,2,3,5,<u>5</u>,6,6,8,10,15,20,29.

5 is the median.

So, to get the IQR we need to get the Q1 (median of the first half)  and Q3 (median of the second half):

Q1 = <u>1,2,2,</u>2<u>,2,3,5,</u> 5,6,6,8,10,15,20,29

Q1 = 2.

Q3 = 1,2,2,2,2,3,5,5 ,<u>6,6,8,</u><u>10</u><u>,15,20,29</u>

Q3 = 10.

Now, to calculate the IQR:

IQR = Q3-Q1

IQR=10-2

IQR=8.

Therefore, the interquartile range (IQR) of the data set is 8.

4 0
3 years ago
Read 2 more answers
Simplify: (x1/2y3)6<br> A) x12y18 <br> B) x12y9 <br> C) x3y18 <br> D) x3y9
MAXImum [283]
The Answer is C




Reason
7 0
2 years ago
Two consecutive integers have a sum of 73. Find the integers.
patriot [66]

<u>Here's how to do it using algebra:</u>

Let the smaller integer be 'x' .  Then the larger integer is (x+1).

Their sum is (x) + (x+1).

That's (2x + 1) .

The problem says their sum is 73, so we can write . . . 2x + 1 = 73 .

Subtract 1 from each side . . . 2x = 72

Divide each side by 2 . . . x = 36

The smaller integer is 36 .

The larger integer is (x+1) .  That would be 37.

The two consecutive integers are  <em>36 </em> and  <em>37</em> .

_______________________________________

<u>Here's how to do it using your brain:</u>

-- If they were both the same number, then their sum would be double it, and each integer would be half of  73 .

-- That's 36.5 .

-- But  36.5  is not even an integer, so neither integer can be 36.5.  Is there something we can do to a pair of 36.5s to make them whole numbers (integers), make them different, and make them consecutive, but not let their sum change ?

-- Well, if we slice off a piece from one of them and glue it onto the other one, then we'll wind up with two numbers that are different, and their sum won't change.

-- What happens if we take the  .5  off of one of them and glue it onto the other one ?   Then one of the 36.5s shrinks to become  <u>36</u>, and the other one grows to become  <u>37</u> .

-- Well whaddaya know !  Now we have two numbers that are consecutive integers, and they add up to  73 .  Great move !

4 0
3 years ago
Read 2 more answers
Which correctly uses bar notation to represent the repeating decimal for 6/11?
Alexandra [31]

Answer:

C

Step-by-step explanation:

i took the quiz

8 0
3 years ago
Suppose that the Bureau of Labor Statistics reports that the entire adult population of Mankiwland can be categorized as follows
melamori03 [73]

Answer:

c. 93.3%

Step-by-step explanation:

The formula and the computation of the  labor-force participation rate is shown below:

Labor-force participation rate = Labor force ÷ Adult population

where,

Labor force = Employed people + unemployed people

                   = 25 million + 3 million

                   = 28 million

And, the adult population is

= 25 million + 3 million + 1 million + 1 million

= 30 million

So, the labor force participation rate is        

= 28 million ÷ 30 million

= 93.3%        

8 0
3 years ago
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