In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
Given that:
mArc R V = mArc V U,
Angle S O R = 13 x degrees
Angle T O U = 15 x - 8 degrees
<h3>How to calculate the angle TOU ?</h3>
∠SOR = ∠TOU (Vertically opposite angles are equal).
Therefore:
13 x = 15x - 8
Subtracting 13x from both sides
13x - 13x = 15x - 8 - 13x
0 = 15x - 13x - 8
2x - 8 = 0
Adding 8 to both sides:
2x - 8 + 8 = 0 + 8
2x = 8
2x/2 = 8/2
x = 4
∠SOR = 13x
= 13(4)
= 52°
∠TOU = 15x - 8
= 15(4) - 8
= 60 - 8
= 52°
Let a = mArc R V = mArc V U
Therefore:
mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)
Substituting:
a + a + 52 = 180
2a = 180-52
2a = 128
a = 128/2
a= 64°
mArc R V = mArc V U = 64°
In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
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I think B not 100%shure ,you could prob go ask this on yahoo and get a bit more help ;) sorry I couldent help more
Answer: lmk
Step-by-step explanation:
Complete question:
Rich is comparing the cost of maintaining his car with the depreciation value of the car.
The value starts at $20,000 and decreases by 15% each year. The maintanance cost is $500 the first year and increases by 28% per year.
When will the maintenance cost and the value be the same.
Answer:
9 years
Step-by-step explanation:
Depreciation is modeled by an exponential function :
A = p(1 - r)^t [decrease, '-']
A = 20,000(1 - 0.15)^t
A = 20000(0.85)^t - - - (1)
Maintainace cost :
A = p(1 + r)^t ; [increase, '+']
A = 500(1 + 0.28)^t
A = 500(1.28)^t - - - (2)
Equating (1) and 2
20000(0.85)^t = 500(1.28)^t
1.28^t / 0.85^t = 20000/500
(1.28 / 0.85)^t = 40
Take log of both sides
Log (1.28 / 0.85)^t = log 40
t * 0.1777910 = 1.6020599
t = 1.6020599 / 0.1777910
t = 9.01
t = 9 years
Answer:
Explanation:
[ Step One ] Factor 
[ Step Two ] Rewrite Equation
[ Step Three ] Factor 
[ Step Four ] Rewrite Equation
[ Step Five ] Cancel Out Common Factor 
