Step-by-step explanation:
that is very simple. you do understand the word "perimeter" ? it just means the distance when walking around the whole shape once.
and that clearly means to just add all side lengths.
that's it.
so, 25 + 18 + 18 + 20 + 17 = 98 ft
was there any other problem with this you did not understand ?
Answer:
or ![(-\infty, 47/6]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%2047%2F6%5D)
Step-by-step explanation:
Note that
.
Also, note that
.
So, the inequality is really equal to
.
We can then add
to both sides to get
.
So, the solution is
, or in interval notation, ![(-\infty, 47/6]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%2047%2F6%5D)
7.5*.2=1.5
- 1.5= 6.5 w/ 20% off
6.5*0.0525=0.34125- rounded= .34+6.5=
$6.84
Hope this helps!!!!
Answer:
th part of the field is covered in the second sprint.
Step-by-step explanation:
A football player is running the length of a 100 yard long football field.
Let player sprints x yards with the speed = 2 yards per second.
So time taken to cover x yards player will take time =
seconds
Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = 
=
seconds
Now total time taken by the player can be represented by the equation

Now we can solve this equation for the value of x.

x + 100 = 40×4
x + 100 = 160
x = 160 - 100 = 60 yards
And length of the second part will be = 100 - 60 = 40 yards
Now the fraction of the field covered by the player in second sprint will be
= 
=
or 40%
Therefore,
th part of the field was covered in second sprint.
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>