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Sauron [17]
3 years ago
11

A right triangle is shown Enter the value of x.

Mathematics
2 answers:
hjlf3 years ago
8 0

Answer:

Step-by-step explanation:

use the pythagorean theorem.

a^2+b^2=c^2

6^2+8^2=c^2

36+64=100

√100=10

***IMPORTANT. don't forget to square root the answer you get from a^2+b^2. you are putting the answer in squared form which isn't going to be correct, so don't forget to root it before you enter.

aleksandr82 [10.1K]3 years ago
4 0

Answer:

10

Step-by-step explanation:

Using $A^2 + B^2 = C^2$, we know that $A = 6$ and $B = 8$. $8^2 = 64$ and $6^2 = 36$. $64 + 36 = 100$, and $√100 = 10$.

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Find the perimeter of the figure shown to the right.
tia_tia [17]

Step-by-step explanation:

that is very simple. you do understand the word "perimeter" ? it just means the distance when walking around the whole shape once.

and that clearly means to just add all side lengths.

that's it.

so, 25 + 18 + 18 + 20 + 17 = 98 ft

was there any other problem with this you did not understand ?

8 0
2 years ago
Given: x - 6.3333 ≤ 1.5 .
Inessa05 [86]

Answer:

x or (-\infty, 47/6]

Step-by-step explanation:

Note that 6.3333 = 6 1/3 = 19/3 = 38/6.

Also, note that 1.5 = 1 1/2 = 3/2 = 9/6.

So, the inequality is really equal to x-38/6.

We can then add 38/6 to both sides to get x.

So, the solution is x, or in interval notation, (-\infty, 47/6]

3 0
3 years ago
$7.50 admission 20%off 5.75% taz total is
pickupchik [31]
7.5*.2=1.5 
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$6.84
Hope this helps!!!!
5 0
3 years ago
A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of
notka56 [123]

Answer:

\frac{2}{5}th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = \frac{x}{2} seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = \frac{Distance}{Speed}

= \frac{100-x}{4} seconds

Now total time taken by the player can be represented by the equation

\frac{x}{2}+\frac{100-x}{4}=40

Now we can solve this equation for the value of x.

\frac{2x+100-x}{4}=40

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= \frac{40}{100}

= \frac{2}{5} or 40%

Therefore, \frac{2}{5}th part of the field was covered in second sprint.

5 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
Read 2 more answers
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