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3 years ago

12

I need help ASAP! 20 point

1 answer:

topjm [15]3 years ago

4 0

Answer:

A) y = 6x + 8

Step-by-step explanation:

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How do you know which standardized test statistics you will use? A Z or T?

Slav-nsk [51]

Answer:

If you're taking the AP Statistics test, you'll need to know the general formula for a standardized test statistic. Standardized test statistics are used in hypothesis testing. The general formula formula is: Standardized test statistic: (statistic-parameter)/(standard deviation of the statistic).

Step-by-step explanation:

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3 years ago

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What is the solution set of (3x - 1)^2 = 5?<br><br><br> HEEEELLLLLLLLLLLPPPPPPPPP

babunello [35]

*I'll be keeping the solutions in exact form*

So firstly, square root both sides. This will split the equation into two:

$3x-1=\sqrt{5} \\ 3x-1=-\sqrt{5}$

Next, add 1 on each side: $3x=\sqrt{5}+1 \\ 3x=-\sqrt{5}+1$

Next, divide 3 on both sides, and your answers will be $x=\frac{\sqrt{5}+1}{3},\frac{-\sqrt{5}+1}{3}$

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3 years ago

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

sorry please be a bit more clear on what help you would like

8 0

2 years ago

Determine the dimensions of a rectangular solid (with a square base) with maximum volume if its surface area is 529 square meter

Zielflug [23.3K]

Answer:

$x=23/\sqrt{6}$ ,

$y= \frac{23}{6\sqrt{6}}$

Step-by-step explanation:

From the question we are told that

Surface area is 529 square meters

Generally the dimensions of the cuboid

$v=x^y$

$D=4xy+2x^2 =529$

$V=x^29(\frac{529-6x^2}{4x})$

$V' =529-6x^2/4$

$v'=0$

Therefore

$529=6x^2$

$x=\sqrt{\frac{529}{6} }$

$x=23/\sqrt{6}$

Mathematically

$v''=\frac{12x}{4}$

$v''=-3\frac{23}{\sqrt{6} }$

$y= \frac{529-2*(\frac{529}{6} }{4*\frac{23}{\sqrt{6} } }$

$y= \frac{23}{6\sqrt{6}}$

Therefore

$x=23/\sqrt{6}$

and

$y= \frac{23}{6\sqrt{6}}$

7 0

3 years ago

Chang and Carlotta solve this problem in two different ways.

ELEN [110]

Answer:

1. a variable

2. the same as

3. the same

hope this helps

8 0

4 years ago