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makvit [3.9K]
3 years ago
13

Combine like terms (x+y)+(x+y)+(x+y)+(x+y) the combine like terms is

Mathematics
2 answers:
Marina CMI [18]3 years ago
5 0

Answer:

4x+4y

Step-by-step explanation:

Combine the four "x" so x+x+x+x likewise the four "y" y+y+y+y.

love history [14]3 years ago
3 0

Answer:

It is 4x + 4y.

Step-by-step explanation:

All you have to do is add all of the y's toghther and then add all of the x's toghther.

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PLSSS HELP IF YOU TURLY KNOW THISS
KonstantinChe [14]

Answer: x=5

Step-by-step explanation:

\frac{2x+0.8}{9}=1.2

\mathrm{Multiply\:both\:sides\:by\:}9

\frac{9\left(2x+0.8\right)}{9}=1.2\cdot \:9

\mathrm{Simplify}

2x+0.8=10.8

\mathrm{Subtract\:}0.8\mathrm{\:from\:both\:sides}

2x+0.8-0.8=10.8-0.8

Simplify

2x=10

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2x}{2}=\frac{10}{2}

Simplify

x=5

7 0
3 years ago
Read 2 more answers
Solve the given right triangle for its missing angle and side measures.
siniylev [52]

Answer:

m∠D = 55°, DE ≈ 8.40 units, DF ≈ 14.65 units

Step-by-step explanation:

got it right on the test

5 0
3 years ago
The length of a rectangular picture is 17 inches and the perimeter is 60 inches. find the width
Mice21 [21]
I got 255.

Perimeter= 60
60/4=15
15*17=255
8 0
3 years ago
A=6 cm,b=9cm,and c =3 cm
Crazy boy [7]
The lengths of sides a and c add to 9 cm, the length of side b.
In a triangle, the the sum of the lengths of any two sides must be greater than the the length of the third side. These dimensions do not make a triangle.

Is this really what you meant? Why did you use capital A for a side? Or is A an angle, and it measures 6 deg, not 6 cm?
4 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
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