<u>Answer:</u>
Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4
<u>Solution</u>:
Need to find the value of x which satisfies following two given expressions
12x − 39 ≤ 9 ------(1)
−4x + 3 < −6 ------ (2)
Lets first solve expression (1)
12x − 39 ≤ 9
Adding 39 on both sides , we get
12x−39 + 39 ≤ 9 +39
=>12x ≤ 48
=> x ≤ 48/12
=> x ≤ 4
Now solving expression (2)
−4x+3<−6
=> -4x < -6 – 3
=> -4x < -9
=> 4x > 9
=> x > 9/4
=> x > 2.25
So from solution of expression (1) and (2) , we get x ≤ 4 and x > 2.25
Hence required value of x is 2.25 < x ≤ 4.
C+2c+6c+C
Here is a problem that work for your question
-3(-x)-6=-3x+10
-3 -3
(-x)-6=-3x+7
-6 -6
(-x)=-3x+1
i only got this far!! im so sorry!!
<span>10,000 x 100,000 = 100,000,000 </span>
Answer:
2 minutes
Step-by-step explanation:
Just divide 16 and 8.
Hope this helped you!
