Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
Answer:
#include<iostream>
using namespace std;
int main()
{
int a,b,c;
cout<<"enter the value of a:";
cin>>a;
cout<<"enter the value of b:";
cin>>b;
cout<<"enter the value of c:";
cin>>c;
cout<<"product is:"<<(a*b*c);
return 0;
}
Explanation:
An Output report is known to be the various findings that has been generated or it is said to be the result of a given program outcome.
<h3>What is an output report?</h3>
An output is known to be a file that has been produced by the system when a user is said to have submitted a Program, Report Set, etc. for execution.
Note that to be able to compile the GPSSWorld program, one has to use a statistical software to create the output and charts, and then one can copy and paste the results unto any given word processor software where one can construct a table for it.
Learn more about output reports from
brainly.com/question/11599232
#SPJ1
Answer:
E. 7.0
Explanation:
the 7 of the out of the older and make a shame of waves and force of trying
