3 years ago

(cosx - sinx)(secx + cscx) = cotx - tanx

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

The answer is (-∞,∞). I hope this helps, have a good day!

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Dividing rational expressions

Galina-37 [17]

$\bf \textit{difference of squares}
\\ \quad \\
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a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
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\\\\\\
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