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3 years ago

(cosx - sinx)(secx + cscx) = cotx - tanx

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

The answer is (-∞,∞). I hope this helps, have a good day!

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Need help <br> what is 1+1

OlgaM077 [116]

It is 2 hope this helps

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2 years ago

Read 2 more answers

There are 24 students in a science class .Mr Sato will give each pair of students 3 magnets .so far,Mr Sato has given 9 pair of

BartSMP [9]

9 pairs = 18 people
24 - 18 = 6
6 divided by 2 = 3 pairs
3 magnets for 3 pairs is 9 magnets.

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3 years ago

In right triangle ABC, B = 51° and AB = 14. BC = _____

liq [111]

The final angle has an angle measure of 115 degrees.

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3 years ago

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

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2 years ago

Which is the best first step when solving the following system of equations? 5 c + 4 d = 10. 3 c + 2 d = 16. Multiply the first

Virty [35]

Answer:

5c+4d=10

3c+2d=16

8c+6c=26

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2 years ago