1 pint=0.5 quarts.
122 pints=61 quarts.
To find the midpoint of line FG, we have to use the following midpoint formula , which is

In the given question,
x1= -5, y1= -3 , x2=-3, y2=3
Substituting the values of x1,y1,x2 and y2 in the formula of the midpoint, we will get

So the midpoint of the given line is (-4,0) and hence the correct option is the first option .
Answer:
25*3*8=600
Step-by-step explanation:
25 students has 3 markrers for each then 25*3 is 75, after that marker come in packages of 8,so 75*8 is 600 packages.
Answer: (3b + 5)(3b - 5)
Because both terms, 9b² and 25, are perfect squares, you can factor by taking the square roots of both terms.
The square root of 9b² is 3b (3b × 3b = 9b²).
The square root of 25 is 5 (5 × 5 = 25).
9b² - 25 has a negative, so the factored expression would be
(3b + 5)(3b - 5). The signs (+ and -) alternate in this case because the expression, 9b² - 25, has no middle term.
You can check your work by using FOIL. See the attachment below.
F irst
O utside
I nside
L ast
A hockey puck is sliding on frictionless ice on an infinite hockey rink.
Its speed is 36 km/hour. How far does the puck slide in 10 seconds ?
(36 km/hr) x (1,000 m/km) x (1 hr/3600 sec) x (10sec) =
(36 x 1,000 x 10 / 3,600) meters = <em>100 meters</em>
What is the puck's speed in miles per hour ?
(36 km/hr) x (0.6214 mi/km) = <em>22.37 mi/hr</em>