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Tpy6a [65]
4 years ago
8

Need help ASAP please and thank you

Mathematics
1 answer:
noname [10]4 years ago
8 0

Answer:

-3m^{12}{n^{6} }

Step-by-step explanation:

To begin simplifying this, we can first divide the coefficients, giving us:

\frac{-3m^{5}n^{4}  }{m^{-7} n^{-2} }

We know that when dividing exponents, this means we need to subtract the exponent on the denominator from the numerator. This gives us:

\frac{-3m^{5+7} n^{4+2} }{1}

Now, simplifying this gets:

-3m^{12}{n^{6} }

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For this cylinder the radius r = 6.8 inches and the height L = 14.2 inches. Which is the BEST estimate for the volume? (Use π =
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Answer:

2062.79 inches cubed

Step-by-step explanation:

Formula- πr2h

=  π×6.82×14.2

=  656.608π

=  2062.7948690883 inches cubed

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3 years ago
A population of a city is 30 000 and decreases 3% each year. If this trend continues. what will the population be after 10 years
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Step-by-step explanation:

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POINTS, AND BRAINLIEST
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The identification of parts A,B andC is illustrated below with their various reasons given.

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Read 2 more answers
Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative. f"(x) = 2x + 9e
ad-work [718]

Answer:

f(x)=\frac{x^3}{3}+9e^x+Cx+D

Step-by-step explanation:

The function <em>F(x)</em> is an antiderivative of the function <em>f(x)</em> on an interval <em>I</em> if

<em>F′(x)</em> = <em>f(x)</em> for all <em>x </em>in <em>I</em>.

The function <em>F(x) + C</em> is the General Antiderivative of the function <em>f(x)</em> on an interval <em>I</em> if <em>F′(x) = f(x)</em> for all <em>x</em> in <em>I </em>and <em>C</em> is an arbitrary constant.

The Indefinite Integral of <em>f(x)</em> is the General Antiderivative of <em>f(x)</em>.

\int {f(x)} \, dx =F(x)+C

To find the first antiderivative you must integrate the function f''(x) = 2x + 9e^x

f'(x)=\int { 2x + 9e^x} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:2xdx+\int \:9e^xdx = x^2+9e^x\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\x^2+9e^x+C

To find the second antiderivative you must integrate the function f'(x) =x^2+9e^x+C

f(x)=\int {x^2+9e^x+C} \, dx\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:x^2dx+\int \:9e^xdx+\int \:Cdx= \frac{x^3}{3}+9e^x+Cx\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\\frac{x^3}{3}+9e^x+Cx+D

Therefore,

f(x)=\frac{x^3}{3}+9e^x+Cx+D

8 0
3 years ago
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