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mezya [45]
2 years ago
14

How many moles of Si are in 78.0 grams of silicon

Chemistry
2 answers:
Igoryamba2 years ago
8 0

Answer:

\boxed {\boxed {\sf 2.78 \ mol \ Si}}}

Explanation:

To convert from grams to moles, we must use the molar mass. This number can be found on the Periodic Table.

  • Si (Silicon): 28.085 g/mol

We can use number as a ratio.

\frac { 28.085 \ g \ Si}{ 1  \ mol \ Si}

Multiply by the given number of grams.

78.0 \ g \ Si *\frac { 28.085 \ g \ Si}{ 1  \ mol \ Si}

Flip the fraction so the grams of silicon cancel.

78.0 \ g \ Si *\frac {1  \ mol \ Si }{ 28.085 \ g \ Si}

78.0  *\frac {1  \ mol \ Si }{ 28.085 }

\frac {78.0  \ mol \ Si }{ 28.085 }= 2.77728324729 \ mol \ Si

The original number of grams (78.0) has 3 significant figures, so our answer must have the same. For the number of moles calculated, that is the hundredth place. The 7 in the thousandth place tells us to round the 7 to a 8.

2.78 \ mol \ Si

There are about 2.78 moles of silicon in 78.0 grams.

gladu [14]2 years ago
6 0
The answer is 2.78 moles of Si

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Answer:

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Explanation:

<u>Step 1:</u> Data given

44.0 J needed

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Initial temperature = 24.9 °C

Final temperature = 36.4 °C

<u>Step 2</u>: Calculate the specific heat of zinc

Q = m*c*ΔT

⇒ with Q = heat (in Joule) = 44.0 J

⇒ with m = the mass of the solid zinc = 10.6 grams

⇒ with c = the specific heat of the zinc = TO BE DETERMINED

⇒ with ΔT = The change in temperature = T2-T1 = 36.4 °C - 24.9 °C = 11.5 °C

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c = 44.0 J / (10.6g * 11.5 °C)

c = 0.361 J/g°C

The specific heat of zinc is 0.361 J/g°C

7 0
3 years ago
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Answer:

C

Explanation:

a variable does that dose not depend on that of another

6 0
2 years ago
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Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

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The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

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The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
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Answer: 588.8 seconds

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Cross multiply:

0.75*x = 120*3.68

x = 120*3.68/0.75

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