Answer:
94.2 g/mol
Explanation:
Ideal Gases Law can useful to solve this
P . V = n . R . T
We need to make some conversions
740 Torr . 1 atm/ 760 Torr = 0.974 atm
100°C + 273 = 373K
Let's replace the values
0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K
n will determine the number of moles
(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)
n = 0.032 moles
This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?
Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol
If the concentration of water inside a cell is higher than the concentration of water outside a cell, osmosis will take place, as water will move from an area of low solute concentration inside the cell to higher solute concentration, outside the cell.
<span>In the electron cloud model, the denser areas represent that there is a great probability that a good number of electrons are ganged up or crowded in that area. The electrons affect the density of some parts of the electron cloud when they condense in those locations.</span>
Answer:
Heat flux = 13.92 W/m2
Rate of heat transfer throug the 3m x 3m sheet = 125.28 W
The thermal resistance of the 3x3m sheet is 0.0958 K/W
Explanation:
The rate of heat transfer through a 3m x 3m sheet of insulation can be calculated as:
![q=-k*A*\frac{\Delta T}{\Delta X}\\\\q=-0.029\frac{W}{m*K}*(3m*3m)*\frac{12K}{0.025m} =125.28W](https://tex.z-dn.net/?f=q%3D-k%2AA%2A%5Cfrac%7B%5CDelta%20T%7D%7B%5CDelta%20X%7D%5C%5C%5C%5Cq%3D-0.029%5Cfrac%7BW%7D%7Bm%2AK%7D%2A%283m%2A3m%29%2A%5Cfrac%7B12K%7D%7B0.025m%7D%20%20%3D125.28W)
The heat flux can be defined as the amount of heat flow by unit of area.
Using the previous calculation, we can estimate the heat flux:
![heat \, flux=\frac{q}{A}=\frac{125.28 W}{9 m^{2} } =13.92 W/m^{2}](https://tex.z-dn.net/?f=heat%20%5C%2C%20flux%3D%5Cfrac%7Bq%7D%7BA%7D%3D%5Cfrac%7B125.28%20W%7D%7B9%20m%5E%7B2%7D%20%7D%20%20%3D13.92%20W%2Fm%5E%7B2%7D)
It can also be calculated as:
![q/A=-k*\frac{\Delta T}{\Delta X}](https://tex.z-dn.net/?f=q%2FA%3D-k%2A%5Cfrac%7B%5CDelta%20T%7D%7B%5CDelta%20X%7D)
The thermal resistance can be expressed as
![\Delta T=R_t*Q\\R_t=\Delta T/Q=\frac{\Delta X}{k*A}](https://tex.z-dn.net/?f=%5CDelta%20T%3DR_t%2AQ%5C%5CR_t%3D%5CDelta%20T%2FQ%3D%5Cfrac%7B%5CDelta%20X%7D%7Bk%2AA%7D)
For the 3m x 3m sheet, the thermal resistance is
![R_t = \frac{\Delta X}{k*A}=\frac{0.025m}{0.029W/mK*9m^{2}}=0.0958 \, K/W](https://tex.z-dn.net/?f=R_t%20%3D%20%5Cfrac%7B%5CDelta%20X%7D%7Bk%2AA%7D%3D%5Cfrac%7B0.025m%7D%7B0.029W%2FmK%2A9m%5E%7B2%7D%7D%3D0.0958%20%5C%2C%20K%2FW)