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sammy [17]
3 years ago
13

How much power is required to pull a slad if you use 60j of work in 5 second ​

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

power required=12J/s

Explanation:

work=60J

time=5second

we have to find power

power=\frac{work done}{time taken}

power=\frac{60J}{5s}

power=12j/s

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Please, see attached two figures:

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The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

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