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sammy [17]
3 years ago
13

How much power is required to pull a slad if you use 60j of work in 5 second ​

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

power required=12J/s

Explanation:

work=60J

time=5second

we have to find power

power=\frac{work done}{time taken}

power=\frac{60J}{5s}

power=12j/s

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Hydrocyanic acid, HCN, is a weak acid. (a) Write the chemical equation for the dissociation of HCN in water. (b) Identify the Br
12345 [234]

Answer: a) HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) HCN : acid CN^- :conjugate base.

And, H_2O : base H_3O^+: conjugate acid.

c) HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)

d) NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases H^+ ions in their aqueous states.

The equation for the dissociation of HCN acid is given by:

HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

HCN is loosing a proton, thus it is considered as an acid and after losing a proton, it forms CN^- which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)

d) The chemical equation for dissociation of NaCN in water.

NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) The chemical equation for the reaction of NaCN and HCI

NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

4 0
3 years ago
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