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sammy [17]
3 years ago
13

How much power is required to pull a slad if you use 60j of work in 5 second ​

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

power required=12J/s

Explanation:

work=60J

time=5second

we have to find power

power=\frac{work done}{time taken}

power=\frac{60J}{5s}

power=12j/s

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Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8
zubka84 [21]

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<u>Explanation:</u>

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where,

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Putting values in above equation, we get:

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3 years ago
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olchik [2.2K]

Answer:

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Explanation:

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3 years ago
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irinina [24]
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