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3 years ago

What happens ????????

Chemistry

2 answers:

Lemur [1.5K]3 years ago

6 0

The air pressure changes

ivolga24 [154]3 years ago

5 0

Correct me if I wrong but I think it's "c"

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A laser produces 17.0 mW of light. In 4.00 hr , the laser emits 6.04×1020 photons. What is the wavelength of the laser?

Vlad [161]

The unit 'mW' means milliwatts. It is a unit of work. There are 1,000 milliwatts in a 1 Watt of work. In 4 hours, there are 14,400 seconds.

Work= Energy/time
17 mW * 1 W/1000 mW = Energy/(14,400 seconds)
Solving for energy,
Energy = 244.8 J
Energy/photon = 244.8 J/(6.04×10²⁰) = 4.053×10⁻¹⁹ J/photon

Using the Planck's equation:

E = hc/λ
where h = 6.626×10⁻³⁴ m²·kg/s, c = 3,00,000,000 m/s and λ is the wavelength

4.053×10⁻¹⁹ J/photon = (6.626×10⁻³⁴ m²·kg/s)(3,00,000,000 m/s)/λ
λ = 4.9×10⁻⁷ m or 49 micrometers

5 0

3 years ago

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_Mg+_O2=_MgO<br> Balance out this reaction above

Ira Lisetskai [31]

2 Mg + 1 O2 = 2 MgO.

8 0

2 years ago

El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónic

Serjik [45]

Explanation:

12 hours ago

El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónico. Si disponemos de 8 mL de H2SO4 al 37 %P/P (d=1,26 g /mL), los cuales se disolvieron hasta alcanzar un volumen de solución de 400 mL, con una densidad de 1,08 g/mL. (La densidad del soluto es corresponde a 1,83 g/cm³)

5 0

3 years ago

How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature

Stels [109]

The first step to answering this item is to convert the given temperatures in °F to °C through the equation,

°C = (°F - 32)(5/9)

initial temperature: 72°F

  °C = (72 - 32)(5/9) = 22.22°C

final temperature: 145°F

  °C = (145 - 32)(5/9) = 62.78°C

Substituting to the equation,

H = mcpdT

H = (43 g)(0.903 J/g°C)(62.78 - 22.22)

H = 1574.82 J

<em>Answer: 1574.82 J</em>

3 0

3 years ago

1- A sample of gas is in a 3.00 L contain at a pressure of 740.0 mmHg. What is the new pressure of the sample if the container's

inna [77]

Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

<h3>What is Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

P1×V1=P2×V2

<h3>New pressure</h3>

In this case, you know:

P1= 740 mmHg
V1= 3 L
P2= ?
V2= 1.25 L

Replacing in Boyle's law:

740 mmHg× 3 L=P2× 1.25 L

Solving:

P2= (740 mmHg× 3 L) ÷ 1.25 L

P2= 1,776 mmHg

Finally, the new pressure of the sample is 1,776 mmHg.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

7 0

2 years ago

Read 2 more answers