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larisa [96]
3 years ago
15

Please help and quickly please and 20 points with brainelest Thank you

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

The answer is 34

Step-by-step explanation:

Order of operation is P.E.M.D.A.S. , or parenthesis, exponents, multiplication or division, then addition or subtraction.

  • 3(12-9)+5²   Parenthesis
  • 3(3)+5²   Exponents
  • 3(3)+25   Multiplication
  • 9+25   Addition
  • 34   Answer
uysha [10]3 years ago
5 0

Answer: The answer is B. 34

Step-by-step explanation:

3(12−9)+5^2

=(3)(3)+5^2

=9+5^2

=9+25

=34

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Evaluate the following limit:
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If we evaluate the function at infinity, we can immediately see that:

        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

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<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

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                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

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