Answer:
4.86 × 10^-7m
Explanation:
Wavelength = C/f
C (Speed) of light = 3 × 10^8
f = 6.17 × 10^14
Wavelength = (3 × 10^8)/ (6.17 × 10^14)
= 4.86 × 10^-7m
Electrolysis of water involves the decomposition of water into oxygen and hydrogen gas by passing an electric current through water. The positively charged ion (hydrogen ion) moves to the negative electrode (cathode) during electrolysis, while the negatively charged ion (OH-) moves to the positive electrode (anode). Therefore, the half equation that occurs at the cathode during the electrolysis of water will be;
4H+(aq) + 4e- = 2H2 (g)
It is crystalline in nature which is used in explosives,buffers and fertilisers it is also used to treat low blood levels(hypokalemia)
Answer:
13.5 * 10^-2 g
Explanation:
What we know:
Balanced Equation: 3Ba+Al2(SO4)3 -->2Al+3BaSO4,
Grams of Ba: 1
Grams of Al2(SO4)3: 1.8g
Calculate the # of moles of Ba and Al2(SO4)3:
1g Ba/137.3 = 7.3 *10^-3 mol Ba
1.8g Al2(SO4)3/ 342 = 5.3 *10^-3 mol Al2(SO4)3
Find the limiting reactant:
Ba has a coefficient of 3 in the balanced equation, so we divide the # of moles of Ba by 3 to get... 7.3 *10^-3 mol Ba/3 = 2.43 *10^-3
Al2(SO4)3 has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 *10^-3
2.43 *10^-3 is smaller than 5.3 *10^-3, therefore Ba is the limiting reactant.
finally, we just find the number of moles of Al
The ratio of Al to Ba is 2:3 so...
7.3 * 10^-3 * (2/3) = 5 *10^-3 mol Al
CONVERT TO GRAMS
5 *10^-3 mol Al * 27 = 13.5 * 10^-2 g
<u>Hope that was helpful! </u>
Answer:
Question: The Haber-Bosch process involves the combination of nitrogen and hydrogen at high temperatures in the presence of a catalyst to produce ammonia. It is currently the main industrial source of ammonia.
Explanation: