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Alex
3 years ago
15

The electron

Chemistry
1 answer:
LekaFEV [45]3 years ago
3 0
The electron B. is the smallest part of an atom.
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Kendall wants to determine if there is a trend in air temperature changes during April . Which procedure should she chose?
Alexeev081 [22]
I think the answer is A
7 0
3 years ago
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For which of the following aqueous solutions would one expect to have the largest van’t Hoff factor (i)? a. 0.050 m NaCl b. 0.50
ira [324]

Answer:

The van't hoff factor of 0.500m K₂SO₄ will be highest.

Explanation:

Van't Hoff factor was introduced for better understanding of colligative property of a solution.

By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.

a) For NaCl the van't Hoff factor is 2

b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]

Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.

c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.

7 0
3 years ago
PLEASE HELP ASAP!!!
alexdok [17]

Answer:

Answers are bellow.

Explanation:

The element with electron configuration 1s22s22p63s1 belong I A group in the periodic table and it is sodium because it loses one electron.

We have periodic table in attachments.

Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table, because it has a single electron in its outer shell, which it readily donates, creating a positively charged ion—the Na+ cation. Its only stable isotope is 23Na.

The free metal does not occur in nature, and must be prepared from compounds.

It is soft metal, reactive and with a low melting point.

8 0
2 years ago
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Which of the following is true about homogeous mixtures
sergey [27]
Was there supposed to be a picture?
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2 years ago
I need help how do you do this ?
Karolina [17]
Sorry, haven't came across that as of yet.
7 0
3 years ago
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