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Alex
3 years ago
15

The electron

Chemistry
1 answer:
LekaFEV [45]3 years ago
3 0
The electron B. is the smallest part of an atom.
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Balance the reaction. <br> CaO(s) + SO3(g) → CaSO4(s)
Reika [66]

Answer:

CaO + SO 3 → CaSO. 4

This is an acid-base reaction (neutralization): CaO is a base, SO 3 is an acid.

3 0
3 years ago
Read 2 more answers
A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem
Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat gained  = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = 0.0923cal/g^oC      

\Delta T=\text{Change in temperature} 

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC

Now put all the given values in the above formula, we get the final temperature of copper.

299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)

T_{final}=87.29^oC

Therefore, the final temperature of the copper is, 87.29^oC

4 0
4 years ago
What are the two products in complete combustion reactions?
JulsSmile [24]

Answer: Combustion is also known as burning, and the substance that burns is usually referred to fuel.  The products of a complete combustion reaction include carbon dioxide (CO2) and water vapor (H2O).

Explanation:

8 0
3 years ago
Read 2 more answers
What is the difference between an atom and a compound?
puteri [66]
An atom cannot be broken down any smaller whereas a compound is made up of atoms and can be broken down into smaller pieces (the individual atoms that make it up)
Hope this helps!
6 0
4 years ago
Read 2 more answers
An unknown substance has the composition of 77.87% c, 11.76% h and 10.37% o. the compound has a molar mass of 154.25 g/mole. wha
frutty [35]
We need to first calculate the empirical formula. Empirical formula is the simplest ratio of whole numbers of components in a compound,
Mass percentages have been given. We need to then calculate for 100 g of the compound 
                               C                     H                           O
mass                    77.87 g              11.76 g                 <span>10.37 g
number of moles  77.87/12            11.76/1                 10.37/16
moles                  = 6.48                  = 11.76                 =0.648
divide by least number of moles 
                              6.48/0.648       11.76/0.648            0.648/0.648
                              = 10                 =18.1                      = 1
rounded off
C - 10 , H - 18 and O - 1
empirical formula - C</span>₁₀H₁₈O
mass of empirical unit = 12 x 10 + 1x 18 + 16 = 120 + 18 + 16 = 154 
number of empirical units = molecular mass / mass of one empirical unit 
                                         = 154.25 / 154 = 1.00 
Therefore molecular formula = C₁₀H₁₈O
6 0
3 years ago
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