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3 years ago

Is water made of plant cells or animal cells •plant •animals •niether

Chemistry

1 answer:

Pepsi [2]3 years ago

5 0

Answer:

i think niether

Explanation:

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How many moles are in 100g of carbon dioxide?

Fantom [35]

Answer:

Explanation:

First, let's find the molar mass of CO₂. This is 12 + 2(16) = 44 g/mole.

Now we can write 100g * (1 mole / 44g) = 2.27 mol, or A. Hope this helps!

7 0

3 years ago

If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi

zlopas [31]

Answer:

$T_{eq}=28.9\°C$

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

$Q_{Cd}+Q_{W}=0$

Thus, we insert mass, specific heat and temperatures to obtain:

$m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0$

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

$T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}$

Now, we plug in to obtain:

$T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C$

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0

3 years ago

What is the mass of 0.257 mol of calcium nitrate?

poizon [28]

Answer: 42.14 g

Explanation: calcium nitrate - $Ca(NO_{3} )_{2}$

, the molar mass of calcium nitrate = 164 g

<h3> formula used = $given mass/molar mass$ = no of moles </h3>

mass required = $0.257*164$

= $42.14$ g

4 0

1 year ago

Which material is a mixture?<br> 1. water<br> 2. air <br> 3. methane<br> 4. magnesium

skelet666 [1.2K]

Pure air is a mixture of several gases that are invisible and odorless. Consists of 78% nitrogen, 21% oxygen, and less than 1% of argon, carbon dioxide.

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3 years ago

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Reflection about the evolution of the book

Setler79 [48]

Answer:

cis the answer

Explanation:

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3 years ago

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