6. a) Team 3 (b/c their numbers were closer apart then the rest)
b)No they were not (can happen you might be precises but not accurate)
c)Team four, (on trial 4)
Answer: I would go with D.
Explanation: Sorry if it is incorrect
Element:- Gold.
Compound:- Sodium Chloride (NaCl).
Ion: an atom that has lost or gained an electron.
Isotopes:- two atoms of hydrogen, each with a different number of neutrons
Cation:- an atom that has developed a positive charge.
Anion: an atom that has gained a negative charge
Answer:
33.8 m
Explanation:
(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).
Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.
Step 2: Convert the mass of HNO₃ to moles.
Step 3: Convert the mass of water to kilograms.
Step 4: Calculate the molality.
(b)
Step 1
In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.
Step 2
The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:
68.0 g × (1 mol/63.01 g) = 1.08 mol
Step 3
The mass of water is 32.0 g = 0.0320 kg
Step 4
The molality of HNO₃ is:
m = moles of solute / kilograms of solvent
m = 1.08 mol / 0.0320 kg
m = 33.8 m
Answer:
1.3 M
Explanation:
1 mole= Concentration * Volume
1 mole=C*0.75 L
C=1.3 M
