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stiv31 [10]
2 years ago
13

If the following are energy returned on investment (EROI) ratios for particular energy sources, which of the following is the mo

st efficient?
3
10:1
48/4
2:1
Chemistry
1 answer:
mixer [17]2 years ago
7 0

Answer:

48/4

Explanation:

The Energy returned on investment is the ratio among the total energy produced and the energy required to produce this final amount.

In this way the biggest the ratio, the biggest is the gain of energy, that is reason why 48/4 = 12 is the biggest ratio, that means that you gain 12 times the energy that you need to produce it.

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What is the Bayer process explain it
Vlada [557]

Answer:

The Bayer process is the principal industrial means of refining bauxite to produce alumina (aluminium oxide) and was developed by Carl Josef Bayer. Bauxite, the most important ore of aluminium, contains only 30–60% aluminium oxide (Al2O3), the rest being a mixture of silica, various iron oxides, and titanium dioxide.

7 0
3 years ago
At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?
ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}

Pressure=\frac{densityXRT}{molarmass}

molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50

Thus molar mass of gas is 37.50g/mol

6 0
3 years ago
Volume can you measured in liters or cubic meters
evablogger [386]
Volume can be measures in liters
5 0
3 years ago
How do I calculate the sum of 6.078 g and 0.3329 g ?
Vesnalui [34]
The answer is 6.4109 grams
8 0
3 years ago
Calculate moles of oxygen atoms in 0.68mol of KMnO4
Dominik [7]
Alright, so that means we have 0.68 mol of the compound


For each 1 mol of the compound, we have 4*1 oxygens (because there are four oxygens in the formula)
Therefore for each 0.68 mol of the compound, we have 4*0.68 moles of oxygen!
6 0
2 years ago
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