1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gala2k [10]
3 years ago
12

How many moles of mercury (II) oxide are needed to produce 65.00 g of mercury?

Chemistry
1 answer:
natima [27]3 years ago
8 0

Answer:

the moles of mercury are nHg = 65/201

HgO --------> Hg + 1/2O2

65/201 65/201

=> the moles of HgO are 65/201 mol

You might be interested in
Plan an investigation to explore the relationship between properties of substances and the electrical forces within those substa
kenny6666 [7]

Answer:

la verdad no se no ablo ingles solo espanis

8 0
2 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 20.4 g g of carbon were burned in the presence
Aleonysh [2.5K]

Answer:

C + O2 -> CO2

C 20.4/12 = 1.7

O 70.4-16.0/16=3.4

CO2 1.7 mol * 44 = 74.8

3 0
3 years ago
Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m
erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3}  =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2}  =0.06882molBr^-

Now, we compute the total moles of bromide:

n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol

Then, the total volume in liters:

150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L

Therefore, the concentration of total bromide is:

M=\frac{0.12338mol}{0.325L}\\\\M=0.380M

Best regards!

8 0
2 years ago
Why does your ankle feels cold when you apply a cold pack to it?
Tresset [83]

Answer:

a.) because your ankle is taking in cold energy from the cold pack

Explanation:

all of the other ones say heat, which is not applied in this question

5 0
3 years ago
What is the molarity of 200 mL of solution in which 2.0<br> molesof sodium bromide is dissolved?
vodomira [7]

Answer:

10 M

Explanation:

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question,

V = 200mL

Since, 1L = 1000mL ,

1 mL = 0.001 L

Hence,

V = 200mL = 0.2 L

n = 2.0 mol

Hence, to calculate the molarity of the solution, the above formula can be used as -

M = n / V

M = 2.0 mol / 0.2 L = 10 M

8 0
3 years ago
Other questions:
  • If i add water to 100 mL of a 0.15M NaOH solution until the final volume 150mL , what will the molarity of the diluted solution
    15·1 answer
  • What are the roles of hydrogen peroxide, oxygen, hydrogen, and catalase in the following chemical reaction?
    9·2 answers
  • Write the charge balance for a solution that contains h , oh–, mg2 , hso4–, so42–, mg(hso4) , mg(oh) , na , and no3–.
    13·1 answer
  • The amount of heat required to produce a given change in temperature can be calculated using the following formula:
    13·1 answer
  • Consider the following half reactions and their standard reduction potential values to answer the following questions.
    5·1 answer
  • Sulphuric acid is a strong acid but acetic acid is weak acid why​
    10·1 answer
  • What’s the difference in the number of protons of an atom of lithium and an atom of chlorine :)) I need this answer quick
    15·1 answer
  • Population from the phylogenetic tree?
    13·1 answer
  • Treading water is used as efficient tool for what?
    5·1 answer
  • By replacing hardware safety features with software controls in the therac-25 machine, aecl was able to?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!