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meriva
2 years ago
8

he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

Chemistry
1 answer:
m_a_m_a [10]2 years ago
8 0

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number (\bar{M_n}) = 1000000 \frac{g}{mol}

Poly condensation degree dependent on the average number of molecular weights is as follows:

DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}

All monomer module, in this case, is propylene  

Sunrise. Unit Wt = Mol. Propylene weight

                           = \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\

DP_n = \frac{1000000}{42.078}\\\\

    =23765.4

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if the volume of a gas at 200.0 kPa is 25.5 L. what is the new volume of the gas at 11.2 atm of pressure?
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Answer: 2.22 litres

Explanation:

Given that,

Original pressure of gas (P1) = 200.0 kPa

[Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere

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Original volume of oxygen O2 (V1) = 25.5L

New pressure of gas (P2) = 11.2 atm

New volume of gas (V2) = ?

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P1V1 = P2V2

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24.8319 atm•L = 11.2 atm•V2

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24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm

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2 years ago
A 15.5 g piece of chromium, heated to 100.0 degrees Celsius, is dropped into 55.5 g of water at 16.5 degrees Celsius. The final
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c_1=2010J/g^0C

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