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meriva
3 years ago
8

he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

Chemistry
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number (\bar{M_n}) = 1000000 \frac{g}{mol}

Poly condensation degree dependent on the average number of molecular weights is as follows:

DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}

All monomer module, in this case, is propylene  

Sunrise. Unit Wt = Mol. Propylene weight

                           = \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\

DP_n = \frac{1000000}{42.078}\\\\

    =23765.4

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Vlad1618 [11]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

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8 0
3 years ago
Use the following balanced reaction to solve:
Naily [24]

Answer:  60.7 g of PH_3 will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}    

\text{Moles of} H_2=\frac{60L}{22.4L}=2.68moles

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H_2 is the limiting reagent as it limits the formation of product and P_4 is the excess reagent.

According to stoichiometry :

6 moles of H_2 produce = 4 moles of PH_3

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3 0
3 years ago
What is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa
Nezavi [6.7K]

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Explanation:

Data given:

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4 0
4 years ago
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5 0
4 years ago
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