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meriva
3 years ago
8

he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

Chemistry
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number (\bar{M_n}) = 1000000 \frac{g}{mol}

Poly condensation degree dependent on the average number of molecular weights is as follows:

DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}

All monomer module, in this case, is propylene  

Sunrise. Unit Wt = Mol. Propylene weight

                           = \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\

DP_n = \frac{1000000}{42.078}\\\\

    =23765.4

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Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the ch
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Explanation:

Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the chemical elements below: a) Na z=11 b) Ca z= 20 c) Sr z 38 d) Li z= 3 e) Cs z= 55 f) Be z= 43

7 0
3 years ago
What is ion, electrons, neutrons?
Serjik [45]

Answer:

Explanation:

Ions:

When an atom lose or gain electron ions are formed.

There are two types of ions anion and cation.

Anion:

When an atom gain electron negative charge is created and anion is formed.

X + e⁻  → X⁻

Cation:

When an atom lose electron positive charge is created and cation is formed.

X   →  X⁺ + e⁻

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10-31 Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

He constructed the glass tube and create vacuum in it. He applied electric current between electrodes. He noticed that a ray of particles coming from cathode to wards positively charged anode. This ray was cathode ray.

Properties of cathode ray:

The ray is travel in straight line.

The cathode ray is independent of composition of cathode.

When electric field is applied cathode ray is deflected towards the positively charged plate.

Hence it was consist of negatively charged particles.

Neutron and proton:

While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P+  

Symbol of neutron= n0  

Mass of proton=1.672623×10-27 Kg

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5 0
3 years ago
How much heat is absorbed when 90.5 g of ice is heated from -11.0 °C to 145.0 °C?
Nadusha1986 [10]

Answer:

Q(total) = 283Kj

Explanation:

5 Heat Transitions …

Specific Heats => c(s) = 0.50cal/g∙⁰C,  c(l) = 1.0 cal/g∙⁰C, c(g) = 0.48 cal/g∙⁰C

Phase Transition Constants => ΔHᵪ = Heat of Fusion = 80 cal/g; ΔHᵥ = Heat of Vaporization = 540cal/g

Note => Phase change regions => no temp. change occurs when 2 phases are in contact (melting and evaporation). Only when single phase substance exists (s, l or g) does temperature change occur. See heating curve for water diagram. The increasing slopes are temperature change regions and heat flow is given by Q =mcΔT. The horizontal slopes are phase changes ( melting & evaporation) and heat flow for each of those regions is given by Q = m·ΔH. Each transition energy is calculated individually (see below) and added to obtain the total heat flow needed.

Q = mcΔT for temperature change regions of the heating curve (single phase only)

Q = m∙ΔH for phase transition regions of the heating curve (2 phases in contact)

Solid (ice) => Melting Pt  => Q(s) = mcΔT = (90.5g)(0.50cal/g∙⁰C)(11⁰C) = 478 cal

Melting (s/l) => Liquid (water) =>   Q(s/l) = m∙ΔHᵪ = (90.5g)(80cal/g) = 7240 cal

Liquid (water) => Boiling Pt => Q(l) = mcΔT = (90.5g)(1.0cal/g∙⁰C)(100⁰C) = 9050 cal

Boiling (l/g) => Gas (steam) => Q(l/g) = m∙ΔHᵥ = (90.5g)(540cal/g) = 48,870 cal

Gas (steam) => Steam @ 145⁰C => Q(g = mcΔT = (90.5g)(0.48cal/g∙⁰C)(45⁰C) = 2036 cal

Total Heat Transfer (Qᵤ) = Q(s) + Q(s/l) + Q(l) + Q(l/g) + Q(g)  

                                 = 478cal +7240cal + 9050 cal + 48,870cal + 2036cal

                                 = 67,674 cal x 4.184 j/cal = 283,148 joules = 283 Kj

4 0
4 years ago
Temperature measures _____. A. the heat content of a material B. the average kinetic energy of particles in a material C. the pr
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4 years ago
How much NaCl would you dissolve and dilute to the 100.00 mL mark in a volumetric flask with DI H2O to prepare a 0.825 M sodium
adoni [48]

Answer:

4.82 g

Explanation:

To solve this problem we'll use the <em>definition of molarity</em>:

  • Molarity = moles / liters

We are given the volume and concentration (keep in mind that 100mL=0.100L):

  • 0.825 M = moles / 0.100 L

Now we <u>calculate the number of NaCl moles required</u>:

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Then we convert 0.0825 NaCl moles into grams, using its molar mass:

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4 0
3 years ago
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