The two parallelograms below are similar.
1 answer:
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Answer:
L'(4, -4)
Step-by-step explanation:
When you're given a midpoint, you can find the point equidistant on the other side of the midpoint by subtracting the relevant coordinate from <em>double that of the midpoint</em>.
Here, the line of reflection is the horizontal line y=-1, so you know only the y-coordinate will change. The reflected point will be ...
(x, y) ⇒ (x, -2-y)
so the point of interest is ...
L' = (4, -2-2) = (4, -4)
