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2 years ago

Can you guys help me with a math problem

Mathematics

2 answers:

quester [9]2 years ago

3 0

Answer:

680.. that is if we are only doing 4 weeks = a month but yeah :)

Step-by-step explanation:

Thepotemich [5.8K]2 years ago

3 0

Answer:

about 680

Step-by-step explanation:

17 months rounds up to 68 weeks so divide by 2 and it would make 34 since jacob is getting the allowance every two weeks then multiply it by 20 which makes 680

i don't know if this is correct but I hope it helps

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I think the answer is 9 1/4

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Answer:

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Step-by-step explanation:

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A construction company is planning to pour concrete for a driveway. The length of the driveway is 16 feet longer that its width

Inga [223]

L (length) = w+16
l x w = Area
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2 years ago

D · 24 = -12 What does d equal?

Darya [45]

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Add all the numbers together, and all the variables

$d*24+12=0$

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3 years ago

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If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

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$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

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1 year ago