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Dovator [93]
3 years ago
9

Heath wants to form a triangle using a piece of wire that is 40 centimeters long. If Heath uses the entire piece of wire, which

could be the side lengths of his triangle?

Mathematics
1 answer:
12345 [234]3 years ago
8 0
I’m pretty sure all of them
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The temperature dropped 2 F every hour for 7 hours. What was the total number of
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multiply 2 * 7 you get 14F

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A coin contains 9 grams of nickel and 16 grams of copper, for a total weight of 25 grams. What percentage of the metal in the co
Leya [2.2K]
X for coin Y for copper
9X+16Y=25
5 0
3 years ago
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Please help with this
snow_lady [41]

Answer:

B. -  \frac{9}{8}

Step-by-step explanation:

\huge\frac{ - 2 {a}^{ - 3} {b}^{2}  }{a}  \\  \\ \huge  =  \frac{ - 2  {b}^{2}  }{a \times{a}^{ 3} }   \\  \\ \huge =  \frac{ - 2  {b}^{2}  }{{a}^{ 4} }   \\  \\  \huge =  \frac{ - 2 \times  {3}^{2} }{ {( - 2)}^{4} }  \\  \\   \huge=  \frac{ - 2 \times 9}{16}  \\  \\  \huge  \red{=  -  \frac{9}{8} }

8 0
2 years ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
2 years ago
Which of the following is the discriminant of the polynomial below x^2+4x+5
steposvetlana [31]

Answer:

\huge\boxed{\sf Discriminant = -4}

Step-by-step explanation:

Comparing it with quadratic equation ax^2 + bx + c = 0, we get:

a = 1 . b = 4 and c = 5

So,

Discriminant = b^2-4ac

D = (4)²-4(1)(5)

D = 16 - 20

D = -4

Hence,

Discriminant = -4

\rule[225]{225}{2}

Hope this helped!

<h3 /><h3>~AH1807</h3>
4 0
2 years ago
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