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3 years ago

What is the domain of h?

Mathematics

1 answer:

iren2701 [21]3 years ago

7 0

Answer:

its actually D :0

Step-by-step explanation:

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Austin is building a miniature replica of the empire state building. the actual empire state building is 1,423 feet tall and 6,0

Fofino [41]

60/6000 = x/1423

100/1 = 1423/x

100x = 1423

x = 14.23 --> About 14 cm

6 0

3 years ago

Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two

mafiozo [28]

Answer:

The difference of the original two-digit number and the number with reversed digits is 18.

Step-by-step explanation:

Since it's a two digit number, let x represent the tens digit and let y represent the units digit.

Thus, the original two digit number is;

10x + y.

The reverse two digit number is;

10y + x.

We are told that five times the sum of the digits of the two-digit number is 13 less than the original number.

Thus;

5(x + y) = (10x + y) - 13

Multiplying out the bracket gives;

5x + 5y = 10x + y - 13

Rearranging gives;

10x - 5x + y - 5y = 13

5x - 4y = 13 - - - - (3)

Also,we are told that, four times the sum of its two digits is 21 less than the reversed two-digit number. Thus;

4(x + y) = (10y + x) - 21 - - - (4)

Simplifying gives;

4x + 4y = 10y + x - 21

>> 10y - 4y - 4x + x = 21

>> 6y - 3x = 21 - - - (4)

Solving eq(3) and (4) simultaneously gives;

x = 5 and y = 3

Thus,

Original number = 53

Reversed number = 35

Difference between original and reversed number = 53 - 35 = 18

6 0

3 years ago

On what interval is the function f(x) = -1272 +452 - 54 decreasing?

vova2212 [387]

Answer:

mume le land mujhe chod na mat sekha

Step-by-step explanation:

laude ke bal

3 0

2 years ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

3 0

3 years ago

What is the value of expression below?

aleksandr82 [10.1K]

$\huge\text{Hey there!}$

$\huge\boxed{\mathsf{\sqrt{49} + 2\times6}}\\\\\huge\boxed{= \mathsf{\bold{7}+ 2\times6}}\\\\\huge\boxed{= \mathsf{7 + \bf 12}}\\\\\huge\boxed{\mathsf{= \bf 19}}\\\\\\\\\huge\text{Therefore, your answer is: \boxed{\mathsf{19}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

2 years ago