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Assoli18 [71]
2 years ago
12

The art teacher has 48 boxes of crayons.

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
8 0

Answer:

3072 Crayons

Step-by-step explanation:

Crayons = C

48C * 64C = 3072C

3072C = 3072 Crayons

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Which function has zeroes at npi/2, where n is an odd integer. Select two of the following that apply.
Andrews [41]

Answer:

y=cosx

y=cotx

Step-by-step explanation:

The trigonometric function;

y=\cos(x) has zeroes at \frac{n\pi}{2} where n is an odd integer.

The trigonometric function; y=cot x=\frac{cosx}{sinx}. This also has zeroes at \frac{n\pi}{2} where n is an odd integer.

4 0
3 years ago
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A prediction from a line graph is
timurjin [86]
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7
Airida [17]

Answer:

$308.50

Step-by-step explanation:

3702 ÷ 12 = 308.5 is her monthly payment

5 0
2 years ago
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3=  \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15

Thus, ad is 15 cm.


4 0
2 years ago
Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today
Hunter-Best [27]

Answer:

Area = 27.5

Step-by-step explanation:

Given

J_{Area} = 440

J_{Width} = 22

K_{Width} = 5.5

<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

K_{Length} = \frac{5.5 * 20}{22}

K_{Length} = \frac{110}{22}

K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

Area = 5.5 * 5

Area = 27.5

4 0
2 years ago
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