Answer:
a. S = {A,B,AB,O}
b. P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45
c. 0.45 = 45% probability that the person chosen at random has either type A or type AB blood
Step-by-step explanation:
a List the sample space for this experiment.
All possible blood types(A, B, AB or O). So
S = {A,B,AB,O}
b Make use of the information given above to assign probabilities to each of the simple events.
The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately .41, .10, .04, and .45, respectively.
So
P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45
c What is the probability that the person chosen at random has either type A or type AB blood
P(A) + P(AB) = 0.41 + 0.04 = 0.45
0.45 = 45% probability that the person chosen at random has either type A or type AB blood
