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abruzzese [7]
3 years ago
5

WILL MARK BR ONLY HAVE 5 MINUTES XTRA POINTS

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

7=A 8= d (I think i did my math correct)

Step-by-step explanation:

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Need help?????????!!!!!!!
julsineya [31]

Answer:

73 and -23 hope this helped hon :)

Step-by-step explanation:

y=-8x+9

plug in -8

y=-8(-8)+9

y=64+9

y=73

y=-8x+9

plug in 4

y=-8(4)+9

y=-32+9

y=-23

3 0
3 years ago
What is the property of 5(11z + 6z + 29) ?
alexira [117]


Associative allows the combining of like terms (Both with variable z)
Distributive allows the 5 to distribute through

5(11z+6z+29)
5(17z+29)
5(17z)+5(29)
<span>85z+145</span>
8 0
4 years ago
Read 2 more answers
Jeremy completes eight extra credit problems on the first day and then for problems each day until the work is complete their 28
Novay_Z [31]

I THINK there is a typo. Instead of "for problems each day", i think it's "four problems each day."

Anyway, we need to find how many days it takes Jeremy to complete the paper.

If he completes 8 problems on the first day and 4 on the rest of the days, after the first day he'll have 28 - 8 = 20 more problems.

And since he does 4 every day with 20 problems: 20 / 4 = 5 days.

7 0
4 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
How many three digit numbers greater than 500 can you form using the digits 2 6 8 exactly once each
LenaWriter [7]
6^8x2  6x2^8 is all i can think of
6 0
3 years ago
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