2 years ago

Use or = to compare the following decimals.

Mathematics

1 answer:

Lynna [10]2 years ago

5 0

The correct answer is B 9.74_98.1

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Which quadratic equation equation is equivalent to (x^2-1)^2 -11(^2-1) +24=0

cluponka [151]

$(x^2-1)^2-11(x^2-1)+24=0$

Use substitution: $x^2-1=t$

$t^2-11t+24=0\\\\t^2-8t-3t+24=0\\\\t(t-8)-3(t-8)=0\\\\(t-8)(t-3)=0\iff t-8=0\ \vee\ t-3=0\\\\t=8\ \vee\ t=3$

<span>we're going back to substitution:

$x^2-1=8\ \vee\ x^2-1=3\ \ \ \ |add\ 1\ to\ both\ sides\ of\ the\ equations\\\\x^2=9\ \vee\ x^2=4$

therefore

$x=\pm\sqrt9\ \vee\ x=\pm\sqrt4\\\\\boxed{x=-3\ \vee\ x=3\ \vee\ x=-2\ \vee\ x=2}$
</span>

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