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lianna [129]
3 years ago
9

PleaSe help ASAP!!

Engineering
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

sulfuric acid.

Explanation:

it hiley curosive

Vera_Pavlovna [14]3 years ago
7 0

Answer:

Sulfuric acid, oxidizers and caustic soda

Explanation:

plato

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3 years ago
10% A steel beam W18x76 spans 32 feet and is subjected to a Moment of 334 kips-ft. Find the load w on the beam. Determine the de
Lilit [14]

Answer:

w = 10.437 kips

deflection at 1/4 span  20.83\E ft

at mid span = 1.23\E ft

shear stress  7.3629 psi

Explanation:

area of cross section = 18*76

length of span = 32 ft

moment = 334 kips-ft

we know that

moment = load *eccentricity

334 = w * 32

w = 10.437 kips

deflection at 1/4 span

\delta = \frac{wa^2b^2}{3EI}

= \frac{10.4375*8^2 *24^2}{3E \frac{BD^3}{12}}

         =\frac{10.437 *8^2*24^2}{3E \frac{18*16^3}{12}}

         = 20.83\E ft

at mid span

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\delta = 1.23\E ft

shear stress

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4 years ago
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