3 years ago

An electric iron has a resistance of 12Ω and takes a current of 2A. Therefore the supply voltage will be

Engineering

1 answer:

Annette [7]3 years ago

3 0

Answer:

24 volts

Explanation:

V=IR

V=2*12

V=24 volts

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snow_lady [41]

Answer:

City planner would be a good answer. Unless there are any options, this seems like the best bet. Hope this helps!

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3 years ago

Read 2 more answers

What is the stress concentration factor of a shaft in torsion, where D=1.25 in. and d=1 in. and the fillet radius is, r=0.2 in.a

klio [65]

Answer:

Concentration factor will be 1.2

So option (C) will be correct answer

Explanation:

We have given outer diameter D = 1.25 in

And inner diameter d = 1 in and fillet ratio r = 0.2 in

So $\frac{r}{d}$ ratio will be $=\frac{0.2}{1}=0.2$

And $\frac{D}{d}$ ratio will be $=\frac{1.25}{1}=1.25$

Now from the graph in shaft vs torsion the value of concentration factor will be 1.2

So concentration factor will be 1.2

So option (C) will be correct answer.

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3 years ago

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Kazeer [188]

Answer:

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3 years ago

You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then

Contact [7]

Answer:

let number = 0

while number < 1

begin

print "Enter a positive integer: "

read number

end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

to an integer value

while currentFactor <= lastFactor

begin

if number is evenly divisible by currentFactor

begin

print currentFactor

let number = number / currentFactor

end

else

let currentFactor = currentFactor + 1

end_if

end

end_while

print a message if number is prime:

if prime == TRUE

print "Your number is prime"

end_if

Explanation:

4 0

3 years ago

The radius of a circle is increased from 5.00 to 5.04 m Estimate the resulting change in area, and then express the estimate as

musickatia [10]

Answer:

1.016%

Explanation:

We need to calculate the rate in the area.

We know that,

$A=\pi r^2$

$A_1=\pi (5)^2 =78.5398m^2\\A_2= \pi(5.04)^2 = 79.8014m^2$

The change in area is

$A_2-A_1=1.2616m^2$

In percentage that represent,

$Rate = \frac{A_2}{A_1} = \frac{79.8014}{78.5398} = 1.016\%$

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3 years ago