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The specific grounding and bonding requirements for an information technology room are located in Article 645.
<h3>What does NEC stand for?</h3>
The National Electrical Code (NEC) is a collection of requirements for the secure installation of electrical wiring in the US that are routinely updated.
Bonding is the joining of conductors that do not convey current, such as enclosures and buildings. Bonded systems are attached to the earth by grounding. To protect persons and property from electric risks, both are required.
Article 645 compliance is optional. The two main pardons provided by Article 645 are. First, underneath a raised floor, non-plenum-rated cables are acceptable. Second, cables, boxes, and similar items for the mentioned IT equipment are exempt from the need for security. sted IT equipment cables, boxes, and the like are not required to be secured in place.
To learn more about NEC refer to:
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Answer:
Wayback machine
Explanation:
Wayback Machine
calls a "three dimensional index". Kahle and Gilliat created the machine hoping to archive the entire Internet and provide "universal access to all knowledge
Answer:No
Explanation:
Given
Block A is at height h and released from rest
Initial Energy possessed by block A is equal to Potential energy of Block which is given by
where m=mass of block
After releasing the block, block first reaches to the bottom of the circle and then uses this energy to reach a top point of the loop.
But as soon as block reaches the top point of the loop it acquires the energy which is equal to Initial energy i.e. all the energy is stored in the form of potential energy and there is no kinetic energy so the block will not able to move further and fall from the top point.
Answer:
293 kg
Explanation:
Let's say the tension in each cable is Tb, Tc, and Td.
First, find the length of cable AD:
r = √(2² + 2² + 1²)
r = 3
Using similar triangles:
Tdx = 2/3 Td
Tdy = 2/3 Td
Tdz = 1/3 Td
Sum of the forces in the x direction:
∑F = ma
Tb − 2/3 Td = 0
Td = 3/2 Tb
Sum of the forces in the y direction:
∑F = ma
2/3 Td − Tc = 0
Td = 3/2 Tc
Sum of the forces in the z direction:
∑F = ma
1/3 Td − mg = 0
Td = 3mg
From the first two equations, we know Td is greater than Tb or Tc. So we need to set Td to 8.6 kN, or 8600 N.
8600 N = 3mg
m = 8600 N / (3 × 9.8 m/s²)
m ≈ 292.5 kg
Rounded to three significant figures, the maximum mass of the crate is 293 kg.
