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3 years ago

13

What's the function of the rubber, square-cut seal positioned around the caliper piston?

1 answer:

lozanna [386]3 years ago

5 0

Explanation:

The square cut seal is what allows the caliper piston to retract back into its housing. Just because you can manually push the piston in, doesn't mean the square cut seal is working. Rapid brake pad wear, brake drag or brake pull are key indicators that the square cut seal is comprised

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A closed system contains propane at 35°c. It produces 35 kW of work while absorbing 35 kW of heat. What is process? the temperat

salantis [7]

Answer:

35°c

Explanation:

Given data in question

heat = 35 kw

work = 35 kw

temperature = 35°c

To find out

temperature of the system after this process

Solution

we know that first law of thermodynamics is Law of Conservation of Energy

i.e energy can neither be created nor destroyed and it can be transferred from one form to another form

first law of thermodynamics is energy (∆E) is sum of heat (q) and work (w)

here we know

35 = 35 + m Cv ( T - t )

35-35 = m Cv ( T-t )

T = t

here T = final temperature

t = initial temperature

it show final temp is equal to initial temp

so we can say temp after process is 35°c

3 0

3 years ago

4. The outer end of a control arm is attached to the steering knuckle through a

arlik [135]

Is attached to the spring

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3 years ago

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What is the net torque about on the bar shown in (figure 1) about the axis indicated by the dot? suppose that ϕ = 30 ∘ and θ = 3

AysviL [449]

EDFFTRGJIKHMHNGBTR56YHUNJ BHYUJHMK.

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2 years ago

A lake is fed by a polluted stream and a sewage outfall. The stream and sewage wastes have a decay rate coefficient (k) of 0.5/d

joja [24]

Solution :

Given :

k = 0.5 per day

$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$

$C_{sw} = 100 \ ppm \ ; \ \ Q_{sw}= 0.5 \ m^3/s$

Volume, V $= 200 \ m^3$

Now, input rate = output rate + KCV ------------- (1)

Input rate $= Q_s C_s + Q_{sw}C_{sw}$

$=(40 \times 10) + (0.5\times 100)$

$= 2 \times 10^5 \ mg/s$

The output rate $= Q_m C_{m}$

= ( 40 + 0.5 ) x C x 1000

$=40.5 \times 10^3 \ C \ mg/s$

Decay rate = KCV

∴ $KCV =\frac{0.5/d \times C \ \times 200 \times 1000}{24 \times 3600}$

= 1.16 C mg/s

Substituting all values in (1)

$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$

C = 4.93 mg/L

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3 years ago

The Hamming encoder/decoder in the lecture detected and corrected one error bit. By adding a thirteen bit which is the exclusive

krek1111 [17]

Cos of error of special characters

The solution has been attached to the portal

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3 years ago