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IrinaK [193]
3 years ago
10

A bag contains 4 red balls and 6 green balls. You plan to select 3 balls at random. Determine the probability of selecting 3 gre

en balls.
Mathematics
2 answers:
Komok [63]3 years ago
8 0
Add the total number of balls and then see how many balls you are pulling and put it into a fraction and then simplify. So it would be 3/10
Pavlova-9 [17]3 years ago
5 0
Total number of balls = 10
Red: 4/10chance of being selected
Green: 6/10 chance of being selected
Basically, there is a way higher chance of selecting 3 green balls and an even HIGHER chance of selecting 6!
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The students in the cooking club brought sugar to class they each brought 3,4,5and 6cups of sugar respectively they divided the
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9. The ticket at right has a perimeter of 42 cm.
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Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

Perimeter =2\times 11 + 4 \times L

This gives

2\times11 + 4 \times L = 42

22 + 4 \times L = 42

Collect like terms

4 \times L = 42-22

4 \times L = 20

Divide both sides by 4

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(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

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Gold = 4 \times 5cm

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(c) The number of gold ink bottles.

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The length of all gold line in the 200 tickets is:

Length = 200 \times Gold

Length = 200 \times 20cm

Length = 4000 cm

Length = 4000 \times 0.01m ---- convert to meters

Length = 40m

Given that:

Bottle = 20m --- 1 bottle for 20 m

The number of bottles (n) is:

n = \frac{Length}{Bottles}

n = \frac{40m}{20m}

n = 2

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

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Answer:13y(x-4)

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